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filter+pop VS reverse+find VS filter+at
(version: 0)
Comparing performance of:
revere and find vs filter and pop vs filter and at
Created:
2 years ago
by:
Guest
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Tests:
revere and find
const arr = [{name: 'jean',index: 1},{name: 'mark',index: 2},{name: 'jean',index: 3}, {name: 'mark',index: 4}] for(let i = 0; i < 10000; i++){ const item = arr.reverse().find(item => item.name === 'jean') }
filter and pop
const arr = [{name: 'jean',index: 1},{name: 'mark',index: 2},{name: 'jean',index: 3}, {name: 'mark',index: 4}] for(let i = 0; i < 10000; i++){ const item = arr.filter(item => item.name === 'jean').pop() }
filter and at
const arr = [{name: 'jean',index: 1},{name: 'mark',index: 2},{name: 'jean',index: 3}, {name: 'mark',index: 4}] for(let i = 0; i < 10000; i++){ const item = arr.filter(item => item.name === 'jean').at(-1) }
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Suite status:
<idle, ready to run>
Run tests (3)
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Test case name
Result
revere and find
filter and pop
filter and at
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Slowest:
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Autogenerated LLM Summary
(model
llama3.1:latest
, generated one year ago):
Let's break down the benchmark test. **What is being tested?** The benchmark is testing three different approaches to find an item in an array based on a specific condition: 1. `reverse()` + `find()`: Reversing the entire array and then using `find()` to locate an item that meets a certain condition (in this case, finding an object with `name` property equal to `'jean'`). 2. `filter()` + `pop()`: Using `filter()` to create a new array containing only items that meet a certain condition (again, finding objects with `name` property equal to `'jean'`), and then using `pop()` to retrieve the last item from the filtered array. 3. `filter()` + `at(-1)`: Similar to the previous approach, but instead of using `pop()`, it uses the new `at()` method (introduced in ECMAScript 2022) to access the last item in the filtered array. **What options are compared?** The three test cases compare the performance of these three approaches: * **`reverse()` + `find()`**: This approach is generally slower because reversing an entire array requires more CPU cycles. * **`filter()` + `pop()`**: This approach creates a new array with all items that meet the condition, which can be memory-intensive if the original array is large. However, it's often faster than reversing the entire array. * **`filter()` + `at(-1)`**: This approach is similar to the previous one but uses the more efficient `at()` method instead of `pop()`. The difference in performance between these two approaches may be small. **Pros and cons:** Here are some pros and cons for each approach: * **`reverse()` + `find()`**: + Pros: Simple implementation. + Cons: Generally slower due to the overhead of reversing an entire array. * **`filter()` + `pop()`**: + Pros: Often faster than reversing the entire array. + Cons: Creates a new array with all items that meet the condition, which can be memory-intensive. * **`filter()` + `at(-1)`**: + Pros: More efficient than using `pop()`. + Cons: May not be available in older browsers or environments (the test results show Chrome 117 running on Mac OS X 10.15.7). **Other considerations** When choosing between these approaches, consider the following: * The size of the original array. * The specificity of the condition being searched for. * The performance requirements of your application. If you need to find an item in a large array frequently, using `filter()` and `at(-1)` might be a good choice. However, if you only need to perform this operation occasionally or with a small array, the simplicity of `reverse()` + `find()` might outweigh its performance limitations. **Library usage** There is no library mentioned in the provided JSON data. The benchmark tests rely solely on built-in JavaScript methods and syntax. **Special JS feature or syntax** The test cases use some modern JavaScript features, including: * Array methods like `filter()`, `pop()`, and `at()` (introduced in ECMAScript 2022). * Arrow functions for simplicity. * Template literals for formatting strings. These features are widely supported in modern browsers and environments.
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