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JavaScript spread operator vs Object.assign performance 2000
(version: 0)
Comparing performance of:
Using the spread operator vs Using Object.assign
Created:
3 years ago
by:
Guest
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Tests:
Using the spread operator
const searchParams = {}; const email = "email" // const email = getCookie("email"); const firstname = "firstname" // const firstname = getCookie("firstname"); const lastname = "lastname" // const lastname = getCookie("lastname"); const phone = "phone" // const phone = getCookie("phone"); // const cookieValues = { // email, // firstname, // lastname, // phone, // }; let cookieValues = {} if (email) { cookieValues.email = email} if (firstname) { cookieValues.firstname = firstname} if (lastname) { cookieValues.lastname = lastname} if (phone) { cookieValues.phone = phone} Object.assign(searchParams, cookieValues);
Using Object.assign
const searchParams = {}; const email = "email"; const firstname = "firstname"; const lastname = "lastname"; const phone = "phone"; Object.assign(searchParams, { email, firstname, lastname, phone, });
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Test case name
Result
Using the spread operator
Using Object.assign
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Autogenerated LLM Summary
(model
llama3.2:3b
, generated one year ago):
Let's break down what's being tested in this benchmark. **Benchmark Definition** The benchmark is comparing two approaches for assigning properties to an object: using the spread operator (`...`) and `Object.assign()`. The benchmark definition provides a sample script that initializes several variables, including `email`, `firstname`, `lastname`, and `phone`. These values are stored in an object called `cookieValues`. **Test Case 1: Using the spread operator** The first test case uses the spread operator to assign properties from `cookieValues` to the `searchParams` object. The syntax is: ```javascript Object.assign(searchParams, cookieValues); ``` This creates a shallow copy of `cookieValues` and merges it with `searchParams`. **Test Case 2: Using Object.assign** The second test case uses `Object.assign()` to assign properties from `cookieValues` to the `searchParams` object. The syntax is: ```javascript Object.assign(searchParams, { email, firstname, lastname, phone }); ``` This creates a shallow copy of an object with only the `email`, `firstname`, `lastname`, and `phone` properties. **Options Compared** The two options being compared are: 1. Using the spread operator (`...`) 2. Using `Object.assign()` **Pros and Cons of Each Approach** **Using the Spread Operator:** Pros: * Concise syntax * Can be more readable for simple assignments Cons: * Can be slower due to the overhead of creating a new object * Limited support in older browsers (pre-ES6) **Using Object.assign():** Pros: * Well-supported across most modern browsers * Can be faster due to optimized implementation * More flexible, as it can handle merging objects with arrays and null values Cons: * Less concise syntax * May require more code for complex assignments **Other Considerations** * Both approaches create a shallow copy of the source object. If you need to merge objects deeply, using `Object.assign()` might be a better choice. * The spread operator is a part of ES6+ syntax, so if you need to support older browsers, `Object.assign()` might be a better option. **Library and Special JS Feature/Syntax** There are no specific libraries mentioned in the benchmark definition. However, it's worth noting that some implementations of `Object.assign()` may use polyfills or workarounds for older browsers. The spread operator is a new JavaScript syntax introduced in ES6+. It allows you to create new objects by spreading the properties of an existing object. **Alternatives** Some alternative approaches to comparing performance might include: * Using a simple loop to iterate over the properties and assign them individually * Using `Object.create()` or other methods for creating new objects * Using `Array.prototype.slice()` or other methods for creating shallow copies
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