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Test checking of literal object types - v2
(version: 0)
Comparing performance of:
prototype vs constructor
Created:
3 years ago
by:
Guest
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Script Preparation code:
var cls = function() {}, f = Object.getPrototypeOf, s = Object.prototype, constructorObject = function(a) { return (!!a) && (a.constructor === Object); }, prototypeObject = function(a) { return f(a) === s; }; var obj = {};
Tests:
prototype
prototypeObject(obj); prototypeObject(new cls);
constructor
constructorObject(obj); constructorObject(new cls);
Rendered benchmark preparation results:
Suite status:
<idle, ready to run>
Run tests (2)
Previous results
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Test case name
Result
prototype
constructor
Fastest:
N/A
Slowest:
N/A
Latest run results:
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Autogenerated LLM Summary
(model
llama3.2:3b
, generated one year ago):
I'll explain the test cases, options compared, and other considerations for the provided JavaScript microbenchmark. **Benchmark Definition** The benchmark measures the performance difference between checking if an object is a constructor (`constructorObject`) versus checking if an object's prototype is equal to the `Object.prototype` (`prototypeObject`). The benchmark creates two objects: `obj` (an empty object) and `cls` (a constructor function). **Options Compared** There are two options being compared: 1. **`prototypeObject(obj)`**: This option checks if the prototype of an object `obj` is equal to `Object.prototype`. It does this by using the `f` variable, which refers to `Object.getPrototypeOf`, and comparing it with `s`, which refers to `Object.prototype`. 2. **`constructorObject(obj)`**: This option checks if the constructor of an object `obj` is equal to `Object.constructor`. It returns a boolean value indicating whether the constructor matches. **Pros and Cons** * **`prototypeObject(obj)`**: + Pros: This approach uses a direct comparison with `Object.prototype`, which might be faster since it doesn't involve a function call. + Cons: If the object's prototype is not equal to `Object.prototype`, this test will still pass, even if the constructor is not a constructor (e.g., if the object has a custom prototype chain). * **`constructorObject(obj)`**: + Pros: This approach checks for a more specific condition (i.e., whether the constructor is an actual constructor). It's more robust than `prototypeObject` since it's less dependent on the order of inheritance. + Cons: This test might be slower due to the function call and comparison operations involved. **Other Considerations** * The benchmark doesn't account for cases where the object has a custom prototype chain, which might affect the results. * The use of `Object.getPrototypeOf` (which is available in modern browsers) ensures that the comparison is done correctly even if the object's prototype is not directly set to `Object.prototype`. * The test creates two objects: `obj` and `cls`. This could potentially introduce overhead due to object creation, but it's likely negligible compared to the performance differences between the two options. **Library/Functionality** The `prototypeObject` function uses `Object.getPrototypeOf`, which is a part of the ECMAScript standard. `Object.prototype` is also a built-in constant in JavaScript. **Special JS Feature/Syntax** There are no special features or syntaxes used in this benchmark that would make it specific to certain browsers or environments. **Alternatives** Other alternatives for measuring object prototype checking performance might include: * Using a library like `fast-prototypes` (which provides an optimized implementation of `Object.getPrototypeOf`) * Creating a custom test function using `Set.prototype.size`, which can be used to measure the number of unique objects * Using a benchmarking framework that supports JavaScript-specific optimization and caching mechanisms
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