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null prototype hasProperty
(version: 0)
Comparing performance of:
using in vs using hasOwnProperty call
Created:
4 years ago
by:
Registered User
Jump to the latest result
Script Preparation code:
o = Object.create(null) o.foo = 'bar' o.baz = 'qux'
Tests:
using in
if ('bar' in o) return true;
using hasOwnProperty call
Object.prototype.hasOwnProperty.call(o, 'bar')
Rendered benchmark preparation results:
Suite status:
<idle, ready to run>
Run tests (2)
Previous results
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Test case name
Result
using in
using hasOwnProperty call
Fastest:
N/A
Slowest:
N/A
Latest run results:
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Autogenerated LLM Summary
(model
llama3.2:3b
, generated one year ago):
Let's break down the benchmark and explain what's being tested, along with their pros and cons. **Benchmark Definition** The benchmark is testing two different ways to check if a property exists in an object. The test cases are: 1. `if ('bar' in o) return true;` 2. `Object.prototype.hasOwnProperty.call(o, 'bar')` **What's being tested?** Both approaches aim to determine whether the `o` object has a property called `'bar'`. **Approach 1: Using `in` operator** This approach uses the `in` operator to check if the property exists in the object. The syntax `if ('bar' in o)` checks if the string `'bar'` is present as a key in the object `o`. If it is, the code inside the `if` statement will execute. **Pros:** * Simple and concise * Fast execution **Cons:** * Can be slower than other approaches because it has to iterate through the object's keys. * Not all objects support the `in` operator, as some may have custom prototype chains that break its behavior. **Approach 2: Using `hasOwnProperty.call()`** This approach uses a static method from the `Object.prototype` to check if the property exists in the object. The syntax `Object.prototype.hasOwnProperty.call(o, 'bar')` checks if the object `o` has a property called `'bar'`. This method returns `true` if the property exists and `false` otherwise. **Pros:** * Fast execution * Can be used with any object, regardless of its prototype chain **Cons:** * Less concise than the `in` operator approach * May require additional imports or namespace resolution for older browsers **Library and Purpose** In this benchmark, no specific library is being tested. However, it's worth noting that both approaches use built-in JavaScript methods (`in` operator) or properties ( `hasOwnProperty.call()`). **Special JS feature/Syntax** There are no special JavaScript features or syntax used in these benchmarks. Now, let's look at the benchmark result: The results show two test cases with different execution times for each approach. The first test case uses the `in` operator and has a higher execution time (5380731.5 executions per second), while the second test case uses `hasOwnProperty.call()` and has a lower execution time (2790085.5 executions per second). **Alternatives** Other alternatives to check if a property exists in an object include: * Using `Object.keys()`, which returns an array of keys for the object, and then checking if `'bar'` is present using `includes()` * Using `Reflect.has()` or `hasOwnProperty()` (if available) methods * Implementing custom checks using `for...in` loops Keep in mind that each approach has its trade-offs, and the choice of which one to use depends on the specific requirements and constraints of your project.
Related benchmarks:
Object.prototype.hasOwnProperty vs obj.hasOwnProperty
Object.prototype.hasOwnProperty vs obj.hasOwnProperty vs exists check
Object.prototype.hasOwnProperty vs obj.hasOwnProperty vs exists check vs 2
Object.prototype.hasOwnProperty vs obj.hasOwnProperty vs Object.hasOwn
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