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testtestasdadadadadsada2
(version: 0)
testtest
Comparing performance of:
from vs spread
Created:
4 years ago
by:
Guest
Jump to the latest result
Script Preparation code:
var x = new Set(); for(let i = 0; i < 10000;i++) { x.add({deep: {deep: {deep: 100}}}) }
Tests:
from
const q = Array.from(x);
spread
const q = [...x]
Rendered benchmark preparation results:
Suite status:
<idle, ready to run>
Run tests (2)
Previous results
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Test case name
Result
from
spread
Fastest:
N/A
Slowest:
N/A
Latest run results:
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Autogenerated LLM Summary
(model
llama3.2:3b
, generated one year ago):
Measuring JavaScript performance is a crucial task, and MeasureThat.net provides a great platform for comparing the execution speed of different approaches. **Benchmark Definition** The provided JSON represents a JavaScript benchmark definition. It contains two essential pieces of information: 1. **Script Preparation Code**: This code is executed before running the actual benchmark test. In this case, it creates a new Set `x` and populates it with 10,000 objects that have nested properties. 2. **Html Preparation Code**: This is an empty string, indicating that no HTML preparation code is required for this benchmark. **Individual Test Cases** The JSON also defines two individual test cases: 1. **"from"`**: This test case measures the performance of using `Array.from(x)` to convert the Set `x` into an array. 2. **"spread"`**: This test case measures the performance of using the spread operator (`[...x]`) to convert the Set `x` into an array. **Options Compared** In this benchmark, two options are compared: 1. Using `Array.from(x)`: This method converts a Set into an array by iterating over its values and creating a new array with those values. 2. Using the spread operator (`[...x]`): This method creates a new array by copying all elements from the Set `x`. **Pros and Cons of Each Approach** Here's a brief summary of the pros and cons of each approach: 1. **Using `Array.from(x)`**: * Pros: Can be more readable, especially for developers familiar with Array.prototype methods. * Cons: May incur additional overhead due to creating an intermediate array. 2. **Using the spread operator (`[...x]`)**: * Pros: More concise and potentially faster, as it avoids creating an intermediate array. * Cons: May be less readable for developers unfamiliar with this syntax. **Library Used** In neither of the test cases is a library explicitly used. However, JavaScript provides built-in methods like `Array.from()` and the spread operator (`[...]`), which are commonly used in modern web development. **Special JS Feature or Syntax** There isn't any special JavaScript feature or syntax mentioned in this benchmark. **Other Alternatives** If you're looking for alternative approaches to convert a Set into an array, consider using `Array.from(x).map()`: ```javascript const q = Array.from(x).map((value) => value); // equivalent to [x] ``` Alternatively, you can use the spread operator (`[...x]`) with `Map.prototype.values()` or other methods that return iterable values: ```javascript const q = [...x.values()]; // equivalent to [x] ``` In summary, MeasureThat.net provides a great platform for comparing the execution speed of different approaches when converting a Set into an array. The two test cases highlight the performance difference between using `Array.from(x)` and the spread operator (`[...x]`).
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testtestasdadadadadsada
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