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Run results for:
Object.fromEntries vs new Map vs Reduce
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<iframe src="https://measurethat.net/Embed?id=610559" width="100%" height="500px"></iframe>
Run details:
User agent:
Mozilla/5.0 (Windows NT 10.0; Win64; x64; rv:139.0) Gecko/20100101 Firefox/139.0
Browser:
Firefox 139
Operating system:
Windows
Device Platform:
Desktop
Date tested:
one year ago
Benchmark engine:
Benchmark.js
Reduce (reusing object)
7K/s
Object.fromEntries with Array.map
4K/s
new Map with Array.map
1K/s
Reduce (creating temporary objects)
0/s
View exact numbers
Test name
Executions per second
✓
Reduce (reusing object)
7,057 Ops/sec
Object.fromEntries with Array.map
3,651 Ops/sec
new Map with Array.map
1,373 Ops/sec
Reduce (creating temporary objects)
0 Ops/sec
Script Preparation code:
var ids = Array.from(Array(10000).keys()) var data = ids.map(item => ({ id: item, random: Math.random() }))
Tests:
Object.fromEntries with Array.map
// Create the dictionary // Using `Object.fromEntries` and `Array.map` const dictionary = Object.fromEntries( data.map((item) => [ // Key item.id, // Item item, ]) ); // Utilize it, to test the performance of the dictionary itself as well. ids.map((id) => dictionary[id]);
new Map with Array.map
// Create the dictionary // Using `new Map` and `Array.map` const dictionary = new Map( data.map((item) => [ // Key item.id, // Item item, ]) ); // Utilize it, to test the performance of the dictionary itself as well. ids.map((id) => dictionary.get(id));
Reduce (reusing object)
// Create the dictionary // Using `Array.reduce` // And reusing the object const dictionary = data.reduce((obj, item) => { obj[item.id] = item; return obj; }, {}); // Utilize it, to test the performance of the dictionary itself as well. ids.map((id) => dictionary[id]);
Reduce (creating temporary objects)
// Create the dictionary // Using `Array.reduce` // And NOT reusing the object const dictionary = data.reduce((obj, item) => { return { ...obj, [item.id]: item }; }, {}); // Utilize it, to test the performance of the dictionary itself as well. ids.map((id) => dictionary[id]);