Run results for: Fastest way of removing items from array 2 that also appear in array 1

Run details:

User agent: Mozilla/5.0 (X11; Linux x86_64; rv:138.0) Gecko/20100101 Firefox/138.0

Browser: Firefox 138

Operating system: Linux

Device Platform: Desktop

Date tested: one year ago

Test name	Executions per second
.filter() with .includes()	911931.2 Ops/sec
.map()	996270.4 Ops/sec

HTML Preparation code:

<!--your preparation HTML code goes here-->

Script Preparation code:

var a1 = ["fox", "drawing", "art", "animal", "posture", "fur", "sketch", "creativity", "playful", "standing", "wildlife", "illustration", "detail", "nature", "creative expression", "artist", "unique", "tail", "stance", "animal behavior", "whimsical", "illustration style", "fine art", "drawing techniques", "imaginative", "hand-drawn"];
var a2 = ["dance", "celebration", "lights", "fox", "drawing", "art", "colors", "whimsical", "floor", "party", "evening", "creative expression", "artist", "unique", "tail", "stance", "shadows", "entertainment", "people", "socialize", "energy", "rhythm", "colorful", "bright", "texture", "ambiance", "nightlife", "mood", "design", "pattern", "event space", "nightlife scene", "sound", "celebration area"];

Tests:

.filter() with .includes()
const uniqA = a1.filter((x) => !a2.includes(x))
.map() with .includes()
const uniqA2 = []; a1.map((x) => !a2.includes(x) ? uniqA2.push(x) : x)

Run results for: Fastest way of removing items from array 2 that also appear in array 1

What is the fastest way of removing items from array2 that are in array1. filter vs includes vs map

.filter() with .includes()

.map() with .includes()