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2substr
(version: 0)
Comparing performance of:
first vs second
Created:
6 years ago
by:
Guest
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Tests:
first
let s = "helo"; s.replace(s.substr(0,1), s.substr(0,1).toUpperCase());
second
let s = "helo"; s[0].toUpperCase() + s.substr(1);
Rendered benchmark preparation results:
Suite status:
<idle, ready to run>
Run tests (2)
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Test case name
Result
first
second
Fastest:
N/A
Slowest:
N/A
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Autogenerated LLM Summary
(model
llama3.2:3b
, generated one year ago):
I'd be happy to explain what's being tested in the provided benchmark. **Benchmark Overview** MeasureThat.net is a website that allows users to create and run JavaScript microbenchmarks. The goal of this benchmark is to measure the performance of different approaches for extracting a specific substring from a string. **What is being tested?** The benchmark tests two approaches for extracting the first character of a string: 1. `s.substr(0, 1)` (Approach 1) 2. `s[0].toUpperCase() + s.substr(1)` (Approach 2) **Options Compared** The benchmark compares the performance of these two approaches on a sample string "hello". **Pros and Cons of Each Approach:** * **Approach 1: `s.substr(0, 1)`** + Pros: - Simple and straightforward. + Cons: - May involve creating a new array or substring object, which can be memory-intensive for large strings. - May not be the most efficient way to extract a single character from a string. * **Approach 2: `s[0].toUpperCase() + s.substr(1)`** + Pros: - Only involves accessing and manipulating existing characters in the original string, which can be more memory-efficient. - May be faster since it doesn't involve creating new objects or arrays. + Cons: - More complex and may require a higher level of JavaScript proficiency. **Library and Special JS Features** There are no libraries or special JavaScript features used in this benchmark. The code only uses built-in JavaScript methods and syntax. **Alternative Approaches** Other possible approaches to extract the first character from a string might include: * Using `s.charAt(0)` (which is equivalent to `s[0]` but may be more efficient) * Using a regular expression (`s.match(/^\w/)[0]`) * Using a custom function or utility library specifically designed for substring extraction However, these alternatives are not being tested in this benchmark.
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