Benchmark: Space numbers every 3 digits

Tests:

Using map+reverse+join
"112345678".split("").reverse().map((x,i)=>{ if((i + 1) % 3 === 0){ return " "+x; } else { return x; } }).reverse().join("");
Using reduce
"12345678" .split("") .reverse() .reduce((acc, cur, i) => (((i + 1) % 3 === 0 ? ' ' : '') + cur + acc) , "").trim();

Rendered benchmark preparation results:

Previous results

Test case name	Result
Using map+reverse+join
Using reduce

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Related benchmarks:

Space numbers every 3 digits (version: 0)