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eval vs Json.parse
(version: 0)
Comparing performance of:
e vs J.p
Created:
one year ago
by:
Guest
Go to the latest result
Tests:
e
var crop = eval('[1,2,3,4]')
J.p
var crop = JSON.parse('[1,2,3,4]')
Rendered benchmark preparation results:
Suite status:
<idle, ready to run>
Run tests (2)
Previous results
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Test case name
Result
e
J.p
Fastest:
N/A
Slowest:
N/A
Latest run results:
Run details:
(Test run date:
one year ago
)
User agent:
Mozilla/5.0 (X11; Linux x86_64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/130.0.0.0 Safari/537.36
Browser/OS:
Chrome 130 on Linux
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Embed Benchmark Result
<iframe src="https://measurethat.net/Embed?id=562471" width="100%" height="500px"></iframe>
J.p
712K/s
e
535K/s
View exact numbers
Test name
Executions per second
✓
J.p
712,105 Ops/sec
e
534,747 Ops/sec
Autogenerated LLM Summary
(model
gpt-4o-mini
, generated one year ago):
The benchmark titled "eval vs Json.parse" explores the performance difference between two JavaScript methods: `eval()` and `JSON.parse()` for parsing JSON strings. Both methods are utilized to convert a string representation of an array into a JavaScript object, but they have different characteristics, pros, cons, and use cases. ### Test Cases Explained 1. **Test Case Using `eval()`**: - **Definition**: `var crop = eval('[1,2,3,4]')` - **Test Name**: "e" The `eval()` function in JavaScript evaluates a string as JavaScript code. In this example, it takes a string representation of an array, interprets it, and executes it, returning the array `[1, 2, 3, 4]`. **Pros**: - Flexible: `eval()` can execute any JavaScript code passed to it, making it powerful for certain dynamic coding scenarios. **Cons**: - Security Risk: Because `eval()` executes any code, it can introduce severe security vulnerabilities, especially when handling untrusted or user-generated data. - Performance: `eval()` can be slower due to the overhead of executing JavaScript code at runtime, compared to direct object creation or parsing. - Code Clarity: Use of `eval()` can obscure the intent of code and lower maintainability. 2. **Test Case Using `JSON.parse()`**: - **Definition**: `var crop = JSON.parse('[1,2,3,4]')` - **Test Name**: "J.p" `JSON.parse()` is a method specifically designed to parse JSON strings into JavaScript objects. In this case, it converts the JSON string `'[1,2,3,4]'` into the array `[1, 2, 3, 4]`. **Pros**: - Security: `JSON.parse()` is safe to use even with untrusted content, as it only parses valid JSON and does not execute any scripts. - Performance: Tends to be faster than `eval()` for typical JSON parsing tasks due to optimized parsing engines in JavaScript engines. - Clarity: The purpose is explicit, making the code more readable and maintainable. **Cons**: - Limited Scope: `JSON.parse()` can only parse strict JSON; it cannot execute arbitrary JavaScript code. - No scripting: Lacks the flexibility of evaluating function calls or executing complex expressions. ### Benchmark Results According to the latest benchmark results: - The `JSON.parse()` method achieved **712,105.31 executions per second**. - The `eval()` method achieved **534,746.69 executions per second**. This indicates that `JSON.parse()` not only is significantly faster than `eval()` but also can be considered a more secure approach when parsing JSON strings. ### Other Considerations - **Alternatives to `eval()` and `JSON.parse()`**: - If parsing simple array-like or object-like strings, one might consider using built-in functions that transform strings into objects without the overhead of code evaluation. - For complex data structures, a library like `lodash` could be helpful, but for parsing JSON specifically, `JSON.parse()` remains best practice. - **Use Cases**: - Use `JSON.parse()` when working with data that adheres to JSON standards, especially when handling responses from APIs. - `eval()` should be avoided in most cases unless there's clear need for executing code dynamically and a full understanding of the potential security risks. In summary, this benchmark highlights the differences in performance and usage of `eval()` versus `JSON.parse()` for JSON string parsing, favoring the more secure and efficient `JSON.parse()` method.
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