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fizzBuzzTes
(version: 0)
Comparing performance of:
fizz1 vs fizz2
Created:
8 years ago
by:
Guest
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Tests:
fizz1
var fizzBuzz = n => [...Array(n)].reduce((acum, value, index) => { const currentNum = index + 1; let num = currentNum; if (currentNum % 5 == 0) num = currentNum % 3 == 0 ? "FizzBuzz" : "Buzz"; if (currentNum % 3 == 0 && num !== "FizzBuzz") num = "Fizz"; acum.push(num.toString()); return acum; }, []);
fizz2
var fizzBuzz = function(n) { let arr = []; for (let i = 1; i <= n; i++) { if (i % 3 === 0 && i % 5 !== 0) { arr.push('Fizz'); } else if (i % 5 === 0 && i % 3 !== 0) { arr.push('Buzz'); } else if ((i % 3 === 0) && (i % 5 === 0)) { arr.push('FizzBuzz'); } else { arr.push(''+i+''); } } return arr; };
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Suite status:
<idle, ready to run>
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Test case name
Result
fizz1
fizz2
Fastest:
N/A
Slowest:
N/A
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Autogenerated LLM Summary
(model
llama3.1:latest
, generated one year ago):
Let's dive into the world of JavaScript microbenchmarks on MeasureThat.net. **Benchmark Overview** The provided JSON represents two test cases, `fizz1` and `fizz2`, which are variations of the classic FizzBuzz algorithm. The goal is to compare the execution speed (measured in executions per second) of these two implementations on a specific browser version (Safari 14). **What's being tested?** The FizzBuzz algorithm is a simple program that prints numbers from 1 to `n` with some additional logic: * If the number is divisible by both 3 and 5, print "FizzBuzz". * If the number is divisible by 3 but not 5, print "Fizz". * If the number is divisible by 5 but not 3, print "Buzz". * Otherwise, just print the number. **Test Case 1: `fizz1`** This test case uses an arrow function (`n =>`) to define a `fizzBuzz` function. The implementation uses `Array.prototype.reduce()` to iterate over an array of numbers from 1 to `n`, and accumulates the results in an array. Here's the relevant code snippet: ```javascript var fizzBuzz = n => [...Array(n)].reduce((acum, value, index) => { const currentNum = index + 1; let num = currentNum; // ... ``` **Test Case 2: `fizz2`** This test case uses a traditional function (`function (n) { ... }`) to define a `fizzBuzz` function. The implementation uses a `for` loop to iterate over numbers from 1 to `n`, and accumulates the results in an array. Here's the relevant code snippet: ```javascript var fizzBuzz = function(n) { let arr = []; for (let i = 1; i <= n; i++) { // ... ``` **Library/Feature Used** No specific libraries are used in these test cases. However, `Array.prototype.reduce()` is a built-in JavaScript method that's being used in `fizz1`. **Special JS Feature or Syntax** No special features or syntax are used in these test cases. **Pros and Cons of Different Approaches** Both implementations achieve the same result (printing numbers from 1 to `n` with additional logic). However, there are differences in approach: * `fizz1` uses a more concise arrow function expression. * `fizz2` uses a traditional function definition and a `for` loop. The choice between these approaches depends on personal preference, coding style, or specific requirements. In terms of performance, the results (382435936.0 vs 356236544.0 executions per second) suggest that `fizz1` is slightly faster than `fizz2`. **Other Alternatives** There are other ways to implement FizzBuzz, such as: * Using a simple loop without accumulators (`for (let i = 1; i <= n; i++) { /* logic */ }`) * Utilizing more advanced techniques like memoization or parallel processing These alternatives might have different performance characteristics and trade-offs.
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