Toggle navigation
MeasureThat.net
Create a benchmark
Tools
Feedback
FAQ
Register
Log In
spread vs concat vs unshift
(version: 0)
spread vs concat vs unshift
Comparing performance of:
arrayUnshift vs arrayConcat vs arraySpread
Created:
8 years ago
by:
Guest
Jump to the latest result
Script Preparation code:
var array = [1,2,3];
Tests:
arrayUnshift
array.unshift(0);
arrayConcat
array = [0].concat(array)
arraySpread
array = [0, ...array]
Rendered benchmark preparation results:
Suite status:
<idle, ready to run>
Run tests (3)
Previous results
Fork
Test case name
Result
arrayUnshift
arrayConcat
arraySpread
Fastest:
N/A
Slowest:
N/A
Latest run results:
No previous run results
This benchmark does not have any results yet. Be the first one
to run it!
Autogenerated LLM Summary
(model
llama3.2:3b
, generated one year ago):
I'd be happy to explain the JavaScript microbenchmark provided by MeasureThat.net. **Overview of the Benchmark** The benchmark measures the performance difference between three different ways to add an element to the end of an array in JavaScript: 1. `unshift()` 2. `concat()` 3. `spread` (using the syntax `[...array]`) These operations are commonly used in various scenarios, such as adding a new element to the beginning of an array or merging two arrays. **Options Compared** The benchmark compares the performance of these three approaches: * `unshift()`: This method adds one or more elements to the beginning of an array. * `concat()`: This method returns a new array containing all elements from the original array, followed by any additional elements. * `spread` (using `[...array]`): This is a syntax feature introduced in ECMAScript 2015 that allows spreading an array into another array. **Pros and Cons of Each Approach** Here's a brief summary of each approach: * `unshift()`: + Pros: Efficient for small arrays, as it only needs to update the internal pointers. + Cons: Can lead to slower performance for large arrays due to the overhead of updating multiple elements. * `concat()`: + Pros: More efficient than `unshift()` for large arrays, but creates a new array object, which can be expensive in terms of memory allocation and garbage collection. + Cons: Less efficient than `unshift()` for small arrays. * `spread` (using `[...array]`): + Pros: Fast and efficient, as it only needs to create a new array with the spread elements. + Cons: Requires support for ECMAScript 2015 syntax, which may not be supported by older browsers or environments. **Library and Syntax Used** The benchmark uses the following libraries and syntax: * No external libraries are used in this benchmark. * The `spread` syntax is a built-in feature of JavaScript introduced in ECMAScript 2015. **Other Considerations** When choosing an approach, consider the size of the array, as well as any specific requirements or constraints for your use case. For small arrays, `unshift()` may be sufficient, while larger arrays may benefit from `concat()` or `spread`. Additionally, if you need to perform multiple operations on the same array, it's essential to consider the overhead of creating temporary objects and garbage collection. **Alternatives** If you're looking for alternative approaches, you can also consider: * Using `Array.prototype.slice()` with the spread syntax: `[...array.slice()]` * Using a library like Lodash or Ramda, which provide optimized implementations of array operations. * Using a different data structure, such as an array-like object or a linked list. Keep in mind that these alternatives may have their own trade-offs and performance characteristics, so it's essential to test and evaluate them based on your specific use case.
Related benchmarks:
concat vs unshift vs spread
unshift vs spread vs concat
spread vs concat vs unshift22
Array.prototype.concat vs spread operator (new try)
spread vs concat vs unshift1
Comments
Confirm delete:
Do you really want to delete benchmark?