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findIndex (reversed) vs findIndex performance
(version: 0)
Measuring which is faster
Comparing performance of:
findIndex vs findIndex reverse
Created:
2 years ago
by:
Guest
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Script Preparation code:
var arr = []; var arrRev = []; var i = 0; var j = 0; while (i <= 1E5) arr[i] = i++; while (j <= 1E5) arrRev[j] = j++;
Tests:
findIndex
const index = arr.findIndex(item => item == 1E5);
findIndex reverse
const index = arrRev.length - arrRev.reverse().findIndex(item => item == 1E5) - 1;
Rendered benchmark preparation results:
Suite status:
<idle, ready to run>
Run tests (2)
Previous results
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Test case name
Result
findIndex
findIndex reverse
Fastest:
N/A
Slowest:
N/A
Latest run results:
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Autogenerated LLM Summary
(model
llama3.2:3b
, generated one year ago):
Let's break down the provided benchmark and explain what's being tested, compared, and other considerations. **Benchmark Definition** The benchmark measures the performance of two approaches to find an index in an array: using `findIndex` directly and using `reverse`, finding the length of the reversed array, and then subtracting 1 from the result. **Script Preparation Code** The script prepares two arrays: `arr` and `arrRev`. The first array is populated with numbers from 0 to 100,000, where each number is assigned to an index equal to its value (using `i++`). The second array is populated in reverse order using a similar approach. This creates two arrays of the same length. **Html Preparation Code** There is no HTML preparation code provided. **Individual Test Cases** The benchmark consists of two test cases: 1. **findIndex**: This test case uses the `findIndex` method directly on the original array (`arr`) to find the index of the first occurrence of the value 100,000. 2. **findIndex reverse**: This test case uses a combination of methods to achieve the same result as the first test case: * Reverse the second array (`arrRev`) using `reverse()`. * Find the length of the reversed array using `length`. * Subtract 1 from the length to get the index. 3. **findIndex reverse**: This test case uses a combination of methods to achieve the same result as the first test case: * Reverse the second array (`arrRev`) using `reverse()`. * Find the index of the value 100,000 in the reversed array using `findIndex`. **Library Used** There is no library explicitly mentioned in the benchmark definition. However, the `reverse()` method and the `findIndex` method are built-in JavaScript methods. **Pros and Cons of Each Approach** 1. **Directly using `findIndex`**: * Pros: Simple and concise code. * Cons: May be slower due to the overhead of searching the array. 2. **Using `reverse`, finding length, and subtracting 1**: (Both test cases use this approach) * Pros: Can avoid potential issues with negative indices or arrays with duplicate values. * Cons: + More complex code compared to using `findIndex` directly. + May have additional overhead due to reversing the array. **Other Considerations** * The benchmark measures execution per second, which is a good indicator of performance. However, it's essential to note that this metric can be influenced by various factors such as CPU speed, memory usage, and JavaScript engine optimizations. * The use of `const` and the absence of any error handling code in the script preparation code simplifies the benchmarking process but may not accurately represent real-world scenarios. **Alternatives** If you were to run this benchmark with different approaches or modifications, some alternatives could be: * Using `indexOf` instead of `findIndex` * Adding a check for null values before calling `findIndex` or `indexOf` * Using a more efficient data structure, such as a sparse array or a Set * Optimizing the script preparation code to reduce memory allocation and garbage collection overhead * Running the benchmark with different input sizes or distributions
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