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Math.pow(x,0.5) vs Math.sqrt(x) 12
(version: 0)
Comparing performance of:
Math.sqrt vs sqrt with Math.pow
Created:
3 years ago
by:
Guest
Go to the latest result
Script Preparation code:
var numbers = Array.from(Array(10000), (_,x) => (Math.random()*x));
Tests:
Math.sqrt
numbers.forEach(x => Math.sqrt(x));
sqrt with Math.pow
numbers.forEach(x => x **0.5);
Rendered benchmark preparation results:
Suite status:
<idle, ready to run>
Run tests (2)
Previous results
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Test case name
Result
Math.sqrt
sqrt with Math.pow
Fastest:
N/A
Slowest:
N/A
Latest run results:
Run details:
(Test run date:
one year ago
)
User agent:
Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/132.0.0.0 Safari/537.36
Browser/OS:
Chrome 132 on Windows
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<iframe src="https://measurethat.net/Embed?id=585372" width="100%" height="500px"></iframe>
sqrt with Math.pow
77K/s
Math.sqrt
38K/s
View exact numbers
Test name
Executions per second
✓
sqrt with Math.pow
77,475 Ops/sec
Math.sqrt
37,634 Ops/sec
Autogenerated LLM Summary
(model
llama3.2:3b
, generated one year ago):
Let's break down the benchmark and its components to understand what's being tested. **Benchmark Definition JSON** The provided JSON represents a JavaScript microbenchmark named "Math.pow(x,0.5) vs Math.sqrt(x) 12". The main goal of this benchmark is to compare the performance of two different methods for calculating the square root of a number: `Math.pow(x, 0.5)` and `Math.sqrt(x)`. **Script Preparation Code** The script preparation code generates an array of 10,000 random numbers using `Array.from(Array(10000), (_,x) => (Math.random()*x))`. This is done to ensure that the benchmark has a consistent input size for both methods being compared. **Html Preparation Code** There is no HTML preparation code provided in this example, so we can assume it's not relevant to this specific benchmark. **Individual Test Cases** The benchmark defines two individual test cases: 1. `Math.sqrt`: This test case executes the `numbers.forEach(x => Math.sqrt(x));` code. 2. `sqrt with Math.pow`: This test case executes the `numbers.forEach(x => x ** 0.5);` code. Note that this syntax uses the exponentiation operator (`**`) instead of `Math.pow()`. The `**` operator is a relatively new addition to JavaScript (introduced in ECMAScript 2016) and allows for faster exponentiation calculations. **Pros and Cons** Let's examine the pros and cons of each approach: 1. **Using Math.sqrt()**: Pros: * Widely supported across browsers and platforms. * Easy to read and maintain. Cons: * Might be slower due to potential parsing overhead or rounding errors. 2. **Using Math.pow(x, 0.5)**: Pros: * Can be faster than `Math.sqrt()` for very large inputs. * Offers more control over the calculation (e.g., precision). Cons: * Less readable and less intuitive compared to `Math.sqrt()`. * Might require additional checks for zero or negative input values. **Library Considerations** There is no specific library mentioned in this benchmark, but some libraries like `Big.js` or `Decimal.js` provide more precise arithmetic operations that can be beneficial for certain applications. However, these libraries are not used in this example. **Special JS Feature/Syntax** The `x ** 0.5` syntax uses the exponentiation operator (`**`) to calculate the square root of a number. This is a relatively new addition to JavaScript (introduced in ECMAScript 2016). While it's generally faster than using `Math.pow(x, 0.5)`, it might not be supported by older browsers or platforms. **Other Alternatives** If you want to explore alternative approaches for calculating the square root of a number, here are some options: 1. **Newton's method**: This is an iterative algorithm that can be used to approximate the square root of a number. It has better convergence properties than simple exponentiation methods but requires more computational resources. 2. **Binary search**: This method uses a binary search approach to find the integer closest to the desired square root value. Keep in mind that these alternatives might not be as efficient or readable as using `Math.sqrt()` or `Math.pow(x, 0.5)`.
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x ** 0.5 vs Math.sqrt(x)
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