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Verifica si es par
(version: 0)
EsPar
Comparing performance of:
Resta vs Division
Created:
2 years ago
by:
Guest
Jump to the latest result
Tests:
Resta
const esPar = (x, b = true) => x == 0 ? b : esPar(x - 1, !b); esPar(10);
Division
const esPar = (x) => x % 2 == 0; esPar(10);
Rendered benchmark preparation results:
Suite status:
<idle, ready to run>
Run tests (2)
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Test case name
Result
Resta
Division
Fastest:
N/A
Slowest:
N/A
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Autogenerated LLM Summary
(model
llama3.2:3b
, generated one year ago):
I'll break down the provided benchmark and explain what's being tested. **Benchmark Overview** The benchmark consists of two individual test cases: "Resta" (which translates to "Subtract" in English) and "Division". Both tests are designed to measure the performance of JavaScript code on MeasureThat.net. **Test Case 1: Resta** * Benchmark Definition: ```javascript const esPar = (x, b = true) => x == 0 ? b : esPar(x - 1, !b); esPar(10); ``` This test case uses a recursive function `esPar` to calculate the parity of a number. The function takes two arguments: `x` and an optional `b` parameter with a default value of `true`. If `x` is 0, the function returns the value of `b`. Otherwise, it calls itself recursively with `x - 1` and the negation of `b`. **Pros and Cons:** * Pros: + This implementation uses a recursive approach, which can be easier to understand for some developers. + It avoids explicit loops, which can make the code more concise. * Cons: + Recursive functions can lead to stack overflows for large inputs, as each recursive call creates a new stack frame. + The function's performance may suffer due to the overhead of repeated function calls. **Test Case 2: Division** * Benchmark Definition: ```javascript const esPar = (x) => x % 2 == 0; esPar(10); ``` This test case uses a simple function `esPar` that takes a single argument `x` and returns whether it's even (`x % 2 == 0`). The function is called with the input value `10`. **Pros and Cons:** * Pros: + This implementation is much simpler and more efficient than the recursive approach in Test Case 1. + It uses a built-in operator (`%`) to calculate the remainder, which is typically faster than explicit division. * Cons: + The function's performance may be affected by the presence of floating-point arithmetic if `x` is not an integer. **Libraries and Special Features:** There are no libraries used in these benchmark definitions. However, the use of a custom recursive function (`esPar`) might indicate that the developer has a specific requirement or constraint for this particular problem. **Other Considerations:** When comparing these two test cases, it's essential to consider the trade-off between readability and performance. The recursive approach in Test Case 1 may be more intuitive for some developers, but its potential performance drawbacks should not be overlooked. In contrast, the simple implementation in Test Case 2 prioritizes efficiency over readability. **Alternatives:** If you were to rewrite these benchmark definitions using alternative approaches, here are a few options: * For Test Case 1 (Resta), consider using an iterative approach instead of recursion, which can avoid stack overflow issues: ```javascript function esPar(x) { while (x > 0) { x = x & (x - 1); } return true; // or false depending on the desired behavior } ``` * For Test Case 2 (Division), consider using a more robust method to calculate even numbers, such as using bit manipulation: ```javascript function esPar(x) { return (x ^ x >> 1) === 0; } ``` Keep in mind that these alternative implementations may have different trade-offs and performance characteristics compared to the original benchmark definitions.
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