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slice & spread vs reduce
(version: 0)
Comparing performance of:
slice & spread vs reduce
Created:
3 years ago
by:
Registered User
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Tests:
slice & spread
function removeTodo(id, list) { const indexToRemove = list.findIndex((item) => item.id === id); return [...list.slice(0, indexToRemove), ...list.slice(indexToRemove + 1)]; } const id = 5; const list = [{id: 1, done: false}, {id: 1, done: false}, {id: 1, done: false}, {id: 1, done: false}, {id: 1, done: false}, {id: 1, done: false}, {id: 1, done: false}, {id: 1, done: false}, {id: 1, done: false}, {id: 5, done: false}] const other = removeTodo(id, list)
reduce
function removeTodo(id, list) { return [...list].reduce( (acc, item) => (item.id === id ? acc : [...acc, item]), [] ); } const id = 5; const list = [{id: 1, done: false}, {id: 1, done: false}, {id: 1, done: false}, {id: 1, done: false}, {id: 1, done: false}, {id: 1, done: false}, {id: 1, done: false}, {id: 1, done: false}, {id: 1, done: false}, {id: 5, done: false}] const other = removeTodo(id, list)
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Test case name
Result
slice & spread
reduce
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N/A
Slowest:
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Autogenerated LLM Summary
(model
llama3.2:3b
, generated one year ago):
Let's break down the provided benchmark and explain what's being tested. **Benchmark Purpose** The benchmark is designed to compare two approaches for removing elements from an array in JavaScript: using `slice` and `spread` (also known as the "spread operator") versus using `reduce`. **Approach 1: `slice` and `spread`** This approach uses the following code: ```javascript function removeTodo(id, list) { const indexToRemove = list.findIndex((item) => item.id === id); return [...list.slice(0, indexToRemove), ...list.slice(indexToRemove + 1)]; } ``` The `slice` method returns a new array that includes the elements from the original array up to the specified index. The `spread` operator (`...`) is then used to concatenate this slice with another slice of the original array, starting from the next index. **Pros:** * Easy to read and understand * Well-established pattern in JavaScript **Cons:** * Creates a new array on each execution, which can be memory-intensive for large datasets * May lead to unnecessary copies of elements if the resulting array is not used immediately **Approach 2: `reduce`** This approach uses the following code: ```javascript function removeTodo(id, list) { return [...list].reduce((acc, item) => (item.id === id ? acc : [...acc, item]), []); } ``` The `reduce` method applies a callback function to each element in the array, accumulating a result. In this case, the callback function checks if the current element matches the specified ID and returns either the accumulator (`acc`) or a new array containing the current element. **Pros:** * Only creates one array on execution (although it still uses a temporary variable to store the result) * Can be more efficient than creating multiple arrays with `slice` and `spread` **Cons:** * More complex pattern in JavaScript, potentially harder to read and understand for some developers * Requires understanding of how `reduce` works **Library/Functions Used** None explicitly mentioned in the benchmark definition. However, both approaches rely on built-in JavaScript methods (`slice`, `findIndex`, `reduce`, `spread`) and operators (`...`). **Special JS Features/Syntax** None explicitly mentioned in the benchmark definition. **Alternative Approaches** Other possible ways to remove elements from an array in JavaScript include: * Using a for loop: `for (let i = 0; i < list.length; i++) { if (list[i].id === id) list.splice(i, 1); }` * Using a filter method: `const result = list.filter(item => item.id !== id)` * Using an array method like `filter` or `map` with a callback function Keep in mind that these alternative approaches may have different trade-offs in terms of performance and memory usage compared to the two approaches being benchmarked.
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