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slice vs pop to reduce last element
(version: 0)
Comparing performance of:
slice vs pop
Created:
3 years ago
by:
Guest
Jump to the latest result
Script Preparation code:
var rows = (new Array(1000)).fill(null).map((val,index) => { return {id: `AA${index}`} })
Tests:
slice
const lastId = rows[rows.length - 1].id; for (let i = rows.length - 1; i > -1; i--) { if (rows[i].id !== lastId) { rows.slice(0, i + 1); break; } }
pop
rows.pop()
Rendered benchmark preparation results:
Suite status:
<idle, ready to run>
Run tests (2)
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Test case name
Result
slice
pop
Fastest:
N/A
Slowest:
N/A
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Autogenerated LLM Summary
(model
llama3.2:3b
, generated one year ago):
Let's break down the benchmark and explain what's being tested. The provided JSON represents a JavaScript microbenchmark test case created on MeasureThat.net. The test is comparing two approaches to remove the last element from an array in reverse order: using `slice()` and using `pop()` methods. **Benchmark Definition** The first part of the JSON defines the benchmark itself: ```json { "Name": "slice vs pop to reduce last element", "Description": null, "Script Preparation Code": "var rows = (new Array(1000)).fill(null).map((val,index) => {\r\n\treturn {id: `AA${index}`}\r\n})" } ``` Here, we have a simple array `rows` created with 1000 elements. Each element is an object with an `id` property. **Individual Test Cases** The second part of the JSON defines two test cases: ```json [ { "Benchmark Definition": "const lastId = rows[rows.length - 1].id;\r\nfor (let i = rows.length - 1; i > -1; i--) {\r\n if (rows[i].id !== lastId) {\r\n rows.slice(0, i + 1);\r\n break;\r\n }\r\n}", "Test Name": "slice" }, { "Benchmark Definition": "rows.pop()", "Test Name": "pop" } ] ``` Each test case defines a different approach to remove the last element from the `rows` array in reverse order: 1. **Slice**: The first test case uses the `slice()` method to create a new array from the beginning of the original array up to the current index `i`. This is done to avoid mutating the original array. 2. **Pop**: The second test case simply removes the last element from the array using the `pop()` method. **Libraries and Special Features** There are no libraries used in this benchmark. However, there is a special feature: the use of arrow functions (e.g., `(val,index) => {\r\n\treturn {id: `AA${index}`}\r\n}`). This is a modern JavaScript syntax introduced in ECMAScript 2015. **Options Compared** The two test cases compare the performance of: 1. **Slice**: Using the `slice()` method to remove elements from the beginning of the array up to the current index. 2. **Pop**: Removing the last element directly using the `pop()` method. **Pros and Cons** Here are some pros and cons for each approach: * **Slice**: + Pros: Avoids mutating the original array, which can lead to unexpected behavior in other parts of the code. + Cons: May create a new array object with more memory overhead than needed. * **Pop**: + Pros: Efficient and simple to implement, as it only modifies the array. + Cons: Modifies the original array, which may cause issues if other parts of the code rely on its integrity. **Other Considerations** When considering these two approaches, keep in mind that: * If you're working with large arrays or need to optimize performance, using `pop()` might be a better choice. * However, if you want to avoid mutating the original array or ensure the integrity of the data, using `slice()` might be a better option. As for alternatives, some other approaches could include: * Using `filter()` method to create a new array with only the desired elements * Using `forEach()` method to iterate over the array and remove elements one by one * Using a custom loop or recursive function to achieve the same result However, these alternatives may not be as efficient or intuitive as using `slice()` or `pop()`.
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