Benchmark: optionally chain me up on valentimes day x2

Script Preparation code:

var obj = [0,{a: {b: {c: {d: [1]}}}}];

Tests:

optionally chaining deez
if(obj[1]?.a?.b?.c?.d && obj[1]?.a?.b?.c?.d.length){ let val = obj[1].a.b.c.d[0]};
if deez
if(obj[1].a.b.c.d && obj[1].a.b.c.d.length) { let val = obj[1].a.b.c.d[0];}

Rendered benchmark preparation results:

Suite status: <idle, ready to run>

Previous results

Test case name	Result
optionally chaining deez
if deez

Fastest: N/A

Slowest: N/A

Latest run results:

No previous run results

This benchmark does not have any results yet. Be the first one to run it!

Autogenerated LLM Summary (model llama3.2:3b, generated one year ago):

LLMs can make mistakes. Check important info.

Let's break down the provided benchmark and explain what's being tested.

**Benchmark Overview**

MeasureThat.net is a platform for creating and running JavaScript microbenchmarks. The benchmark in question measures the performance of two different approaches to optionally chaining (also known as optional chaining) in JavaScript.

**Optional Chaining**

In JavaScript, optional chaining (`?.`) is an operator that allows you to access nested properties of an object without throwing an error if any intermediate property does not exist. For example:
```javascript
const obj = { a: { b: { c: 1 } } };
console.log(obj.a.b.c); // returns 1

const obj2 = { a: { b: { c: 1 } } };
console.log(obj2?.a?.b?.c); // returns 1 (thanks to optional chaining!)
```
In the benchmark, two different approaches to optional chaining are being tested:

**Approach 1: Using `?.`**

```javascript
if (obj[1]?.a?.b?.c?.d && obj[1]?.a?.b?.c?.d.length) { let val = obj[1].a.b.c.d[0]; }
```
This approach uses the optional chaining operator (`?.`) to access nested properties of the `obj` object.

**Approach 2: Without `?.`**

```javascript
if (obj[1].a.b.c.d && obj[1].a.b.c.d.length) { let val = obj[1].a.b.c.d[0]; }
```
This approach does not use optional chaining and instead uses the dot notation to access nested properties of the `obj` object.

**Pros and Cons**

* **Approach 1 (with `?.`):**
	+ Pros:
		- More concise and readable code
		- Reduces the risk of null pointer exceptions
	+ Cons:
		- May be slower due to the additional operator evaluation
* **Approach 2 (without `?.`):**
	+ Pros:
		- May be faster due to reduced overhead from optional chaining
	+ Cons:
		- More error-prone code, as null pointer exceptions can occur

**Library and Special JavaScript Features**

There are no libraries or special JavaScript features being used in this benchmark. The focus is solely on measuring the performance of these two approaches.

**Other Alternatives**

If you're interested in exploring other ways to optimize optional chaining, consider the following alternatives:

1. **Memoization**: Cache the results of expensive function calls to avoid repeated computations.
2. **Caching**: Store intermediate results in a cache to reduce the number of times the function needs to be executed.
3. **Loop Unrolling**: Unroll loops to improve performance by reducing overhead from loop control statements.

Keep in mind that these alternatives may not necessarily address the specific performance characteristics of optional chaining, but can help with overall optimization and caching strategies.

I hope this explanation helps you understand what's being tested in this benchmark!

Related benchmarks:

optionally chain me up on valentimes day x2 (version: 0)

Comparing performance of: optionally chaining deez vs if deez

Created: 3 years ago by: Guest

Jump to the latest result

optionally chaining deez

if deez

Suite status: <idle, ready to run>

Fastest: N/A

Slowest: N/A

No previous run results

Autogenerated LLM Summary (model llama3.2:3b, generated one year ago):