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regexp vs func
(version: 0)
Comparing performance of:
regexp vs func
Created:
3 years ago
by:
Guest
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Script Preparation code:
var min = 0; var MAX_CID_VALUE = 268435455; var cid = 200000; var result = null;
Tests:
regexp
result = /^[0-9]{1,9}$/.test(cid) && Number(cid) < MAX_CID_VALUE
func
const val = Number.parseInt(cid); result = isNaN(val) || val > MAX_CID_VALUE || val < 0;
Rendered benchmark preparation results:
Suite status:
<idle, ready to run>
Run tests (2)
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Test case name
Result
regexp
func
Fastest:
N/A
Slowest:
N/A
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Autogenerated LLM Summary
(model
llama3.2:3b
, generated one year ago):
Let's dive into the world of JavaScript benchmarks. **Overview** The provided benchmark definition and test cases compare two approaches to validate if a number (represented by `cid`) meets certain conditions: being within a range of 1-9 digits, being a positive integer less than `MAX_CID_VALUE`. We'll break down each approach, their pros and cons, and other considerations. **Approach 1: Using Regular Expressions (`regexp`)** The first test case uses the `/^[\d]{1,9}$//.test(cid)` expression to validate if `cid` matches the pattern of a number with exactly 1-9 digits. The regular expression works as follows: * `^`: Start of the string * `[\d]`: Match any digit (0-9) * `{1,9}`: Exactly 1 to 9 occurrences of the preceding element (digits) * `$`: End of the string Pros: * Lightweight and efficient, as regular expressions are optimized for performance. * Easy to implement and read. Cons: * Can be slower than other approaches due to the overhead of creating and compiling regular expressions. * May not perform well for very large inputs or complex patterns. **Approach 2: Using `Number.parseInt` and Conditional Statements (`func`)** The second test case uses `Number.parseInt(cid)` to convert `cid` to an integer, and then checks if it's a valid number using three conditional statements: * `isNaN(val)`: Check if the result is NaN (Not a Number) * `val > MAX_CID_VALUE || val < 0`: Check if the value exceeds or drops below the maximum allowed value Pros: * Fast and efficient, as it uses native JavaScript functions. * Easy to read and understand. Cons: * Requires two function calls, which can be slower than using regular expressions. * More complex code can lead to errors if not implemented correctly. **Other Considerations** * **Error handling**: Both approaches assume that `cid` is a valid number. If it's not, the functions may throw an error or return incorrect results. * **Performance**: Regular expressions are generally faster for simple patterns like this one. However, as input sizes increase, other approaches might become more efficient. * **Security**: The regular expression approach is more secure, as it prevents malicious input from being executed. **Benchmarking Libraries** None of the provided test cases explicitly use a dedicated benchmarking library. However, `regexp` uses the `/.../` notation, which is commonly used in JavaScript libraries like Lodash or Ramda for string manipulation and pattern matching. **Special JS Features/Syntax (none)** There are no special features or syntax used in this benchmark that would require additional explanation. **Alternatives** Some alternatives to regular expressions include: * **String.prototype.match()**: A more general-purpose method for searching strings with patterns. * **RegExp.prototype.test()`: An alternative way to test a string against a pattern. * **JSON.parse() and Number.parseInt()**: While not strictly related, these functions can be used in combination with conditional statements to validate numbers. In conclusion, the choice between using regular expressions or `Number.parseInt` and conditional statements depends on performance requirements, code readability, and security considerations. Regular expressions are generally a good choice for simple patterns like this one, while `Number.parseInt` and conditional statements might be preferred for more complex use cases.
Related benchmarks:
RegExp.test() vs String.match()
regexp vs func 2
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parseFloat isNaN vs RegEx parseFloat vs Number isNaN
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