Benchmark: Grad AC - MeasureThat.net

Kyle

function solution(A, D) {
    // combine arrays (removing day for grouping by YYYY-MM)
    const combined = A.map((num, i) => ({ num, date: D[i].substring(0, 7) }))    
    const groupedByDate = combined.reduce((r, a) => {
        r[a.date] = r[a.date] || [];
        r[a.date].push(a);
        return r;
    }, Object.create(null));
    let total = 0;
    let monthsVoid = 0;
    Object.keys(groupedByDate).forEach(date => {
        const arr = groupedByDate[date];
        const expenditures = arr.filter(d => d.num < 0);
        const expendituresTotal = expenditures.reduce((p, c) => p + c.num, 0);
        const incomings = arr.filter(d => d.num >= 0);
        const incomingsTotal = incomings.reduce((p, c) => p + c.num, 0);
        if (expenditures.length >= 3 && expendituresTotal <= -100) {
            monthsVoid += 1;
        }
        total += expendituresTotal + incomingsTotal;
    });

    const result = total - ((12 - monthsVoid) * 5);
    return result;
}

Alicia

function solution(A, D) {
    const balanceBeforeFees = A.reduce((acc, val) => {
        return acc+val;
  }, 0);
  
    const transactions = A.map((ammount, i) => ({ ammount, date: D[i].split('-')[1] })) 
    const transactionPerDate = transactions.reduce((acc, val) => {
        acc[val.date] = acc[val.date] || [];
        acc[val.date].push(val);
      
        return acc;
    }, {});
    let fees = (12 -  Object.keys(transactionPerDate).length) * 5;
 
    
    Object.keys(transactionPerDate).forEach(date => {
        const arr = transactionPerDate[date];
      
        const payments = arr.filter(el => el.ammount < 0);
        const paymentsTotal = payments.reduce((acc, val) => acc + val.ammount, 0);
        
  
     if ((payments.length < 3 || paymentsTotal > -100) || (payments.length < 3 && paymentsTotal > -100) ) {
             fees += 5
        }
     
    });
    
    return balanceBeforeFees - fees;
}

James A

function solution(A, D) {
    const txsPerMonth = {
        01: [],
        02: [],
        03: [],
        04: [],
        05: [],
        06: [],
        07: [],
        08: [],
        09: [],
        10: [],
        11: [],
        12: [],
    };

    D.forEach((date, idx) => {
        txsPerMonth[parseInt(date.split('-')[1], 10)].push(A[idx]);
    })

    let finalTotal = 0;

    Object.values(txsPerMonth).forEach((arr) => {
        let totalTxsOut = 0;
        let totalValueOut = 0;

        let total = arr.reduce((acc, curr) => {
            if (curr < 0) {
                totalTxsOut++;
                totalValueOut -= curr;
            }


            return acc + curr;
        }, 0);

        if (totalTxsOut < 3 || totalValueOut < 100) {
            total -= 5;
        }

        finalTotal += total;
    });

    return finalTotal;
}

Yichao

function solution(A, D) {
    // A is array of transaction amounts, D is array of transaction date.
    // calculate sum of elements in A
    const sum = A.reduce((a, b) => a + b, 0);
    // calculate how many months there are in D
    const DateArray = D.map(date => date.split('-'));
    let monthArray = [];
    for (let i = 0; i < DateArray.length; i++) {
        monthArray.push(DateArray[i][1]);
    }
    const negTransac = A.filter(amount => amount < 0);
    let condition2;
    if ( negTransac.length >= 3) {
        abValue = negTransac.reduce((a, b) => a + b) * -1;
        if (abValue >= 100) {
            condition2 = true;
        } else {
            condition2 = false;
        }
    }

    let monthFinal = (monthArray.includes("01")) || (condition2) ? 11 : 12;

    const totalSum = sum - (5 * monthFinal);
    return totalSum;
}

Keanu

function solution(A, D) {
    // Implement your solution here
    let total = 0;
    let months = new Array(12);
    for(let i = 0; i < 12; i ++) {
        months[i] = new Array();
    }

    for(let i = 0; i < A.length; i ++) {
        let month = D[i].substring(5,7);
        month = parseInt(month);
        months[month -1].push(A[i]);
    }

    for(let i = 0; i < 12; i ++) {
        let noPaidTrasnactions = 0;
        let monthlyTotal = 0;
        let transactions = months[i];
        for(let j = 0; j < transactions.length; j ++) {
            let transaction = transactions[j];
            if(transaction < 0) {
                noPaidTrasnactions ++;
                monthlyTotal += (transaction * -1)
            }
            
            total += transaction;
        }
        if(noPaidTrasnactions < 3 || monthlyTotal < 100) {
            total -= 5
        }
    }
    return total;
}

Grad AC (version: 0)

Comparing performance of: Kyle vs Alicia vs James A vs Yichao vs Keanu

Created: 3 years ago by: Guest

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Kyle

Alicia

James A

Yichao

Keanu

Suite status: <idle, ready to run>

Fastest: N/A

Slowest: N/A

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Autogenerated LLM Summary (model llama3.2:3b, generated one year ago):