Benchmark: remainder or floor

Script Preparation code:

a = 23467
b = 125

Tests:

remainder
c = (a - a % b) / b
floor
c = Math.floor(a / b)

Rendered benchmark preparation results:

Suite status: <idle, ready to run>

Previous results

Test case name	Result
remainder
floor

Fastest: N/A

Slowest: N/A

Latest run results:

No previous run results

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Autogenerated LLM Summary (model llama3.2:3b, generated one year ago):

LLMs can make mistakes. Check important info.

Let's break down the provided JSON and explain what is tested in the benchmark.

**What is being tested?**

The benchmark tests two approaches for integer division:

1. **Remainder-based approach**: This method uses the modulo operator (`%`) to find the remainder of `a` divided by `b`, and then subtracts this remainder from `a`. The result is divided by `b` again.
2. **Math.floor-based approach**: This method uses the built-in `Math.floor()` function, which returns the largest integer less than or equal to the given number.

**Options compared**

The benchmark compares the performance of these two approaches in terms of speed.

**Pros and Cons**

* **Remainder-based approach:**
	+ Pros:
		- Can be faster for smaller values of `a` and `b`, as it avoids the overhead of the `Math.floor()` function.
	+ Cons:
		- May be slower for larger values of `a` and `b`, as it requires more operations to find the remainder and subtract it from `a`.
* **Math.floor-based approach:**
	+ Pros:
		- Generally faster and more efficient, especially for large values of `a` and `b`.
	+ Cons:
		- May be slower for smaller values of `a` and `b`, due to the overhead of the `Math.floor()` function.

**Library usage**

There is no explicit library mentioned in the benchmark definition. However, it's worth noting that the `Math` object, which includes the `floor()` function, is a built-in JavaScript object.

**Special JS features or syntax**

None are explicitly mentioned in this benchmark. However, some older browsers might not support the `Math.floor()` function, so the remainder-based approach might be used as a fallback.

**Other alternatives**

In theory, other approaches to integer division could be tested, such as:

* Using a custom implementation of integer division
* Using a library like `BigInt` for arbitrary-precision arithmetic
* Using a just-in-time (JIT) compiler or other optimization techniques

However, these alternatives are not explicitly mentioned in the benchmark definition.

It's worth noting that this benchmark is testing the performance difference between two specific approaches to integer division, which might not be representative of all use cases. Additionally, the test results should be taken as a general guideline rather than absolute benchmarks for your specific use case.

Related benchmarks:

remainder or floor (version: 0)

Is integer division faster using reminder and subtraction or using Math.floor?

Comparing performance of: remainder vs floor

Created: 3 years ago by: Guest

Jump to the latest result

remainder

floor

Suite status: <idle, ready to run>

Fastest: N/A

Slowest: N/A

No previous run results

Autogenerated LLM Summary (model llama3.2:3b, generated one year ago):