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shift vs pop
(version: 0)
Comparing performance of:
Shift vs Pop
Created:
8 years ago
by:
Guest
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Tests:
Shift
var n = 0; var t = []; while(true) { t[n] = n; n++; if(n==10) break; } n = 0; while(true){ n++; t.shift(); if(n==10) break; }
Pop
var n = 0; var t = []; while(true) { t[n] = n; n++; if(n==10) break; } n = 0; while(true){ n++; t.pop(); if(n==10) break; }
Rendered benchmark preparation results:
Suite status:
<idle, ready to run>
Run tests (2)
Previous results
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Test case name
Result
Shift
Pop
Fastest:
N/A
Slowest:
N/A
Latest run results:
Run details:
(Test run date:
20 days ago
)
User agent:
Mozilla/5.0 (Windows NT 10.0; Win64; x64; rv:150.0) Gecko/20100101 Firefox/150.0
Browser/OS:
Firefox 150 on Windows
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Test name
Executions per second
Shift
3785954.0 Ops/sec
Pop
8005060.5 Ops/sec
Autogenerated LLM Summary
(model
llama3.2:3b
, generated one year ago):
Let's break down the provided JSON benchmark data and explain what's being tested. **Overview** The benchmark compares the performance of two JavaScript operations: `shift` and `pop` on an array `t`. The test creates an array with 10 elements, initializes an index variable `n` to 0, and then uses a while loop to populate the array with values from 0 to 9. After that, it increments `n` and performs either `shift` or `pop` operation on the array. **Options Compared** Two options are being compared: 1. **Shift**: The test pops an element from the beginning of the array using the `shift()` method. 2. **Pop**: The test removes an element from the end of the array using the `pop()` method. **Pros and Cons of Each Approach** **Shift:** Pros: * Can be faster for large arrays since it avoids creating a temporary variable. * Often used when working with arrays that need to be sorted or have a specific order. Cons: * May not be as efficient on smaller arrays since the `shift()` method creates a new array and copies elements from the original array, which can lead to unnecessary memory allocation and copying. **Pop:** Pros: * Can be faster for small arrays since it simply removes the last element without creating a temporary variable. * Often used when working with arrays that need to be modified frequently, like in queue or stack implementations. Cons: * May not be as efficient on large arrays since the `pop()` method creates a new array and copies elements from the original array, which can lead to unnecessary memory allocation and copying. **Other Considerations** The test doesn't account for other factors that might affect performance, such as: * Array size: The benchmark only tests with an array of 10 elements. Larger arrays would likely favor `shift` over `pop`. * Browser engine: Different browser engines (e.g., V8 in Chrome, SpiderMonkey in Firefox) have different optimizations and may perform differently. * JavaScript version: Older or newer JavaScript versions might behave differently. **Libraries and Special JS Features** The test doesn't use any libraries. However, if a library were used to create the array `t` or modify it after populating it with values, we would need to consider the library's impact on performance. If special JavaScript features like async/await or generators were used in the script preparation code, they might affect the benchmark results, but there's no indication of that in the provided JSON data. **Alternatives** Other alternatives for this type of benchmark could include: * Comparing the performance of `shift()` and `pop()` on a more diverse array size range (e.g., 100 elements). * Adding other operations to the test case, like `push`, `splice`, or `slice`. * Using a different data structure, such as a linked list or a binary search tree. * Testing with a larger number of iterations or longer execution times.
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