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Math.Max() vs Ternary
(version: 0)
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Comparing performance of:
ternary vs math
Created:
3 years ago
by:
Guest
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Script Preparation code:
var num1 = Math.random(); var num2 = Math.random();
Tests:
ternary
const max1 = num1 > num2 ? num1 : num2;
math
const max2 = Math.max(num1, num2);
Rendered benchmark preparation results:
Suite status:
<idle, ready to run>
Run tests (2)
Previous results
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Test case name
Result
ternary
math
Fastest:
N/A
Slowest:
N/A
Latest run results:
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Autogenerated LLM Summary
(model
llama3.2:3b
, generated one year ago):
Let's break down the benchmark and explain what is being tested. **Benchmark Purpose** The benchmark measures the performance difference between two approaches to find the maximum of two numbers: using the ternary operator (`? :`) and using the built-in `Math.max()` function. **Options Compared** There are two options being compared: 1. **Ternary Operator**: This approach uses a conditional statement with three parts: if-then-else. The syntax is `condition ? value_if_true : value_if_false`. In this case, it's used to find the maximum of two numbers. 2. **Math.max() Function**: This built-in JavaScript function returns the largest of zero or more numbers. **Pros and Cons** * **Ternary Operator**: + Pros: concise, easy to read, and understand. It can also be used in a wider range of situations beyond just finding the maximum of two numbers. + Cons: slightly slower than `Math.max()` due to the overhead of evaluating the condition and returning one of the values. * **Math.max() Function**: + Pros: highly optimized, fast, and reliable. It's also widely supported across different browsers and devices. + Cons: requires two arguments (the numbers to compare) and may not be as readable or intuitive as the ternary operator. **Library Usage** There is no library being used in this benchmark. **Special JS Features/Syntax** The test case uses a special JavaScript feature/syntax, which is the ternary operator (`? :`). This syntax allows for concise and expressive code that can be more readable than traditional if-then-else statements. **Other Considerations** * The benchmark measures the performance of each approach in terms of executions per second. * The results are likely to vary depending on the specific use case, data size, and other factors. * The benchmark is designed to provide a general idea of the performance difference between these two approaches. **Alternatives** Other alternatives for finding the maximum of two numbers include: 1. Using a loop: `if (num1 > num2) { result = num1; } else { result = num2; }` 2. Using a comparison function: `Math.max()` is often more readable and efficient than writing a custom comparison function. 3. Using a library like Lodash's `maxBy()`: This can provide additional features and optimizations beyond simple maximum finding. Overall, the benchmark provides valuable insights into the performance difference between two common approaches to finding the maximum of two numbers in JavaScript.
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