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splicevspop
(version: 0)
Comparing performance of:
splice vs pop
Created:
3 years ago
by:
Guest
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Tests:
splice
const arr = [0,1,2,3,4,5] const newArr = arr.splice(-3, 3)
pop
const arr = [0,1,2,3,4,5] const newArr = new Array(3) for (i=0; i < 3; i++) { newArr[i] = arr.pop() }
Rendered benchmark preparation results:
Suite status:
<idle, ready to run>
Run tests (2)
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Test case name
Result
splice
pop
Fastest:
N/A
Slowest:
N/A
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Autogenerated LLM Summary
(model
llama3.2:3b
, generated one year ago):
I'll break down the provided JSON and explain what's being tested, compared options, pros and cons of each approach, and other considerations. **Benchmark Definition** The benchmark definition is represented by the following JSON object: ``` { "Name": "splicevspop", "Description": null, "Script Preparation Code": null, "Html Preparation Code": null } ``` This defines a new benchmark with no description, script preparation code, or HTML preparation code. The name of the benchmark is "splicevspop". **Individual Test Cases** The test cases are defined in the following JSON array: ``` [ { "Benchmark Definition": "const arr = [0,1,2,3,4,5]\r\nconst newArr = arr.splice(-3, 3)", "Test Name": "splice" }, { "Benchmark Definition": "const arr = [0,1,2,3,4,5]\r\nconst newArr = new Array(3)\r\nfor (i=0; i < 3; i++) {\r\n newArr[i] = arr.pop()\r\n}", "Test Name": "pop" } ] ``` These two test cases measure the performance of two different approaches to create a new array by removing elements from an existing array. **Approach 1: Using `splice()`** The first test case uses the `splice()` method to create a new array. The benchmark definition is: ```javascript const arr = [0,1,2,3,4,5] const newArr = arr.splice(-3, 3) ``` This approach modifies the original array by removing elements from both ends and returns an array of removed elements. **Approach 2: Using `pop()`** The second test case uses the `pop()` method to create a new array. The benchmark definition is: ```javascript const arr = [0,1,2,3,4,5] const newArr = new Array(3) for (i=0; i < 3; i++) { newArr[i] = arr.pop() } ``` This approach creates a new array and then populates it by removing elements from the original array using `pop()`. **Pros and Cons** * **Using `splice()`:** + Pros: - Modifies the original array in-place, which can be more efficient. - Returns an array of removed elements, which can be useful for further processing. + Cons: - Can modify the original array unexpectedly if not used carefully. - May have a higher overhead due to the method call and parameter passing. * **Using `pop()`:** + Pros: - Does not modify the original array, which can be safer and more predictable. - May have a lower overhead due to the simple method call and return value. + Cons: - Creates an additional object (the new array) that needs to be managed. - Requires multiple iterations over the original array. **Other Considerations** * Both approaches can have performance implications depending on the size of the input array and the number of elements being removed. * The use of `splice()` or `pop()` can also impact memory usage, as it involves creating new arrays or modifying existing ones. * The test cases do not account for edge cases such as empty arrays or arrays with a single element. **Library Usage** There is no library explicitly used in these benchmark definitions. However, the use of modern JavaScript features and methods like `splice()` and `pop()` relies on the standard library provided by the browser or environment. **Special JS Features/Syntax** There are no special JS features or syntax mentioned in the benchmark definitions. The tests only focus on the basic operations of creating a new array using `splice()` or `pop()`.
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