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Array duplicate removal for duplicates exceeding `N`-number
(version: 0)
https://codereview.stackexchange.com/q/175067/120114
Comparing performance of:
original duplicate removal vs 2-pass approach
Created:
8 years ago
by:
Guest
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Tests:
original duplicate removal
// Remove duplicates that occur 3 or more times in an array // keeping unique values and those with less than 3 function removeMany(arr) { const newArr = Array.from(arr).sort() let count = 0; let result = [] newArr.forEach((value, index, ar) => { count += 1; // refactored afterwards from (ar[index + 1] !== value) if (ar.lastIndexOf(value) <= index && count <= 2) { for (var i = 0; i < arr.length; i++) { if (arr[i] === value) { result.push(arr[i]) } } count = 0 } else if (ar[index + 1] !== value) { count = 0; } }); // +1 is there anyway to return a result that mimicks the original order of `numbers`? return result; // [1, 2, 2, 3, 4, 4] } const numbers = [1, 2, 3, 2, 4, 4, 5, 5, 5, 5]; console.log(removeMany(numbers));
2-pass approach
// Remove duplicates that occur 3 or more times in an array // keeping unique values and those with less than 3 function removeMany(arr) { let countMappings = arr.reduce(function(carry, item) { if (carry[item]!== undefined) { carry[item]++; } else { carry[item] = 1; } return carry; }, {}); return arr.reduce(function(final, item) { if (countMappings[item] <3) { final.push(item); } return final; }, []); } const numbers = [1, 2, 3, 2, 4, 4, 5, 5, 5, 5]; console.log(removeMany(numbers));
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Result
original duplicate removal
2-pass approach
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Autogenerated LLM Summary
(model
llama3.2:3b
, generated one year ago):
Measuring the performance of JavaScript microbenchmarks is crucial to optimize code execution and identify bottlenecks. **Benchmark Overview** The provided benchmark measures the performance of two approaches to remove duplicates from an array that occur 3 or more times: 1. **Original Duplicate Removal**: This approach sorts the array, iterates through it, and pushes unique values with a count less than 3 into a new result array. 2. **2-Pass Approach**: This approach uses a mapping object to count occurrences of each element in the array and then filters out elements that occur 3 or more times. **Options Compared** Both approaches have their pros and cons: * **Original Duplicate Removal** * Pros: * Simple and easy to understand * No additional data structure is required (aside from a temporary result array) * Cons: * Sorts the entire array, which can be costly for large datasets * May have performance issues if the array is very large or has many duplicate elements * **2-Pass Approach** * Pros: * More efficient than the original approach (especially for large arrays) * Uses a mapping object to count occurrences, which reduces the number of iterations required * Cons: * Requires an additional data structure (the mapping object) to store counts * May be more complex and harder to understand **Library and Special JS Feature** In this benchmark, there is no specific library or special JavaScript feature being tested. However, the 2-pass approach uses a common JavaScript technique called "mapping" or "counting," which is used to iterate through an array and perform calculations based on each element's value. **Alternative Approaches** Other possible approaches to remove duplicates from an array include: * Using `Set` data structure (e.g., `[...new Set(numbers)]`) * Using a `for...of` loop with a `reduce()` method * Using a library like Lodash or Ramda for functional programming Keep in mind that each approach has its own trade-offs, and the best choice will depend on the specific requirements of your use case.
Related benchmarks:
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