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slice VS splice VS shif vs substr vs substring short
(version: 0)
Comparing performance of:
slice vs splice vs shift vs substr vs substring
Created:
4 years ago
by:
Guest
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Script Preparation code:
var list = []; for (var i = 0; i < 1000; i++) { list.push("IDqualcosaltro"+i); }
Tests:
slice
for (var i = 0; i < 1000; i++) { list.push("IDqualcosaltro"+i); [...list[i]].slice(2); }
splice
for (var i = 0; i < 1000; i++) { list.push("IDqualcosaltro"+i); [...list[i]].splice(2); }
shift
for (var i = 0; i < 1000; i++) { list.push("IDqualcosaltro"+i); let tmp =[...list[i]] tmp.shift(); tmp.shift(); tmp.toString().replaceAll(',','') }
substr
for (var i = 0; i < 1000; i++) { list.push("IDqualcosaltro"+i); list[i].substr(2); }
substring
for (var i = 0; i < 1000; i++) { list.push("IDqualcosaltro"+i); list[i].substring(2); }
Rendered benchmark preparation results:
Suite status:
<idle, ready to run>
Run tests (5)
Previous results
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Test case name
Result
slice
splice
shift
substr
substring
Fastest:
N/A
Slowest:
N/A
Latest run results:
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Autogenerated LLM Summary
(model
llama3.2:3b
, generated one year ago):
Let's break down the provided benchmark and explain what's being tested, compared, and the pros/cons of each approach. **Benchmark Overview** The benchmark is designed to compare the performance of different methods for extracting a subset of characters from an array or string in JavaScript. The tests are: 1. `slice`: Extracts 2 characters from the end of an array using `array.slice(start)`. 2. `splice`: Removes 2 elements from the end of an array using `array.splice(start, length)`. 3. `shift`: Shifts the first two elements of an array and converts it to a string. 4. `substr` (not `substring`, as in some other languages): Extracts 2 characters from the end of a string using `string.substr(start)`. 5. `substring`: Extracts 2 characters from the end of a string using `string.substring(start)`. **Library and Special JS Features** None of these tests explicitly use any libraries, but they do utilize JavaScript's built-in features: * Arrays: `array.slice()`, `array.splice()` * Strings: `string.substr()`, `string.substring()` **Comparison** Each test case extracts 2 characters from the end of an array or string and measures the performance. The goal is to determine which method is the fastest. **Pros and Cons of Each Approach** 1. **`slice()`**: Pros: * Efficient, as it only creates a new array slice. * Simple and easy to implement. Cons: * Can be slower than `splice()` or `shift()` if the array is very large, as it requires creating a new array. 2. **`splice()`**: Pros: * Can be faster for large arrays, as it modifies the original array. Cons: * More complex and harder to implement correctly. * May be slower than `slice()` for small arrays due to the overhead of modifying the array. 3. **`shift()`**: Pros: + Fastest approach, as it only requires two operations: shifting elements and converting to a string. Cons: + Less flexible, as it shifts all elements before the specified index. 4. **`substr()`** (not `substring()`): Pros: + Similar to `slice()`, but uses string methods instead of array methods. Cons: + Inefficient for large arrays or strings, as it requires creating a new string. 5. **`substring()`**: Pros: + Similar to `slice()`, but uses string methods instead of array methods. Cons: + Inefficient for large arrays or strings, as it requires creating a new string. **Other Alternatives** There are other ways to achieve the same result without using these approaches: * Using regular expressions: `new RegExp('\\d{2}$').exec('IDqualcosaltro' + i)[0]` * Using `indexOf()` and slicing: `list[i].slice(list[i].indexOf('IDqualcosaltro' + i) + 5)` (note that this assumes the index is known in advance) * Using a library like Lodash's `chunkAt()`: `_list.chunkAt(2)` * Using a custom solution with a loop and conditional statements Keep in mind that these alternatives may not be as efficient or simple to implement as the original methods.
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