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Small Array.from vs Spread
(version: 0)
Comparing performance of:
Array.from vs Spread
Created:
4 years ago
by:
Guest
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Tests:
Array.from
var fooSet = new Set(); for(var i=0;i<10;i++) { fooSet.add(i); } var other = Array.from(fooSet);
Spread
var fooSet = new Set(); for(var i=0;i<10;i++) { fooSet.add(i); } var other = [...fooSet];
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Suite status:
<idle, ready to run>
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Test case name
Result
Array.from
Spread
Fastest:
N/A
Slowest:
N/A
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Autogenerated LLM Summary
(model
llama3.2:3b
, generated one year ago):
Let's break down the provided JSON data to understand what is being tested on MeasureThat.net. **Benchmark Definition** The benchmark, titled "Small Array.from vs Spread," compares two approaches: `Array.from` and the spread operator (`...`). The benchmark tests which approach creates a new array from a Set object with 10 elements faster. **Options Compared** Two options are compared: 1. **Array.from**: Creates a new array by calling the `Array.from()` method on an iterable, such as a Set. 2. **Spread Operator (`...`)**: Creates a new array by using the spread operator to duplicate each element of the input iterable (in this case, a Set). **Pros and Cons** **Array.from** Pros: * More explicit and readable code * Well-documented and widely supported Cons: * May have additional overhead due to method call and creation of an intermediate array * Not optimized for Set objects specifically **Spread Operator (`...`)** Pros: * Fast and efficient, as it uses a native implementation * Eliminates the need for an intermediate array or method call Cons: * Less explicit and less readable code (due to the spread syntax) * May not be as well-documented or widely supported as `Array.from` **Library** In this benchmark, no specific library is used. However, the Set object is a built-in JavaScript data structure. **Special JS Feature/Syntax** No special JavaScript feature or syntax is mentioned in the provided code snippets. **Other Alternatives** If you're interested in exploring alternative approaches to creating an array from a Set, here are some options: 1. **Using `map()`**: You can use the `map()` method to create a new array from a Set: `var other = [...new Set([0, 1, 2, ..., 9])]` 2. **Using `reduce()`**: You can use the `reduce()` method to create a new array from a Set: `var other = [0, 1, 2, ..., 9].reduce((a, b) => [...a, b])` Keep in mind that these alternatives may have performance implications or require more memory. In summary, the "Small Array.from vs Spread" benchmark on MeasureThat.net compares two approaches to creating an array from a Set object: `Array.from` and the spread operator (`...`). While both methods are efficient, the spread operator is likely to be faster due to its native implementation. The choice between these options ultimately depends on your personal preference for code readability and maintainability versus raw performance.
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