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Array.apply vs Spread new array
(version: 0)
Comparing performance of:
Array.apply (small) vs Spread new Array (small) vs Array.apply (big) vs Spread new Array (big)
Created:
9 years ago
by:
Guest
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Tests:
Array.apply (small)
const array = Array.apply(null, {length: 5});
Spread new Array (small)
const array = [...Array(5)]
Array.apply (big)
const array = Array.apply(null, {length: 100000});
Spread new Array (big)
const array = [...Array(100000)]
Rendered benchmark preparation results:
Suite status:
<idle, ready to run>
Run tests (4)
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Test case name
Result
Array.apply (small)
Spread new Array (small)
Array.apply (big)
Spread new Array (big)
Fastest:
N/A
Slowest:
N/A
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Autogenerated LLM Summary
(model
llama3.2:3b
, generated one year ago):
Let's break down what is tested in the provided JSON and explain the options, pros, cons, and other considerations. **Benchmark Definition** The benchmark measures the performance difference between using `Array.apply()` and the spread operator (`...`) to create a new array of a specified length. **Options Compared** There are two main options compared: 1. **`Array.apply(null, {length: 5})`**: This method uses the `apply()` method on an empty function object (due to `null` being used as the first argument) to specify the length of the new array. 2. **`[...Array(5)]`** or **`const array = Array.from(Array(5))`**: These methods use the spread operator (`...`) to create a new array from an existing one. **Pros and Cons** 1. `Array.apply(null, {length: 5})`: * Pros: This method is more explicit and can be easier to read for those familiar with it. * Cons: It's less efficient than the spread operator due to the overhead of creating a function object. 2. `[...Array(5)]` or `const array = Array.from(Array(5))`: * Pros: These methods are more concise and efficient, as they directly create an array using the spread operator. * Cons: They can be less readable for those not familiar with them. **Library Used** None. The benchmark only uses native JavaScript features. **Special JS Feature or Syntax** The `Spread Operator` (`...`) is used in two of the test cases. It's a relatively recent feature introduced in ECMAScript 2015 (ES6). The spread operator allows for spreading the elements of an array into a new array, and it's often used to create a shallow copy of an existing array. **Other Considerations** * **Cache locality**: When using `Array.apply()`, the function object is created, which can lead to cache locality issues. In contrast, the spread operator creates a new array without creating a separate function object. * **Function creation overhead**: The `apply()` method involves creating a function object and passing it as an argument, whereas the spread operator directly creates an array. **Alternatives** If you were to rewrite this benchmark using different approaches, some alternatives could be: 1. Using `Array.from()` with no arguments (e.g., `Array.from()`) instead of `[...Array(5)]` or `const array = Array.from(Array(5))`. 2. Using a custom function to create an array (e.g., `function createArray(length) { ... }`). 3. Measuring the performance of other methods, such as using `Map` or `Set` instead of arrays. However, these alternatives would likely change the nature of the benchmark and might not provide comparable results to the original spread operator vs. `Array.apply()` comparison.
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