Toggle navigation
MeasureThat.net
Create a benchmark
Tools
Feedback
FAQ
Register
Log In
Immutable to Mutable
(version: 0)
Comparing performance of:
With Serialization vs Spread
Created:
5 years ago
by:
Guest
Jump to the latest result
Tests:
With Serialization
const data = [ { name: "David", age: 16000, }, { name: "David", age: 16000, }, { name: "David", age: 16000, }, { name: "David", age: 16000, }, { name: "David", age: 16000, }, { name: "David", age: 16000, }, { name: "David", age: 16000, } ]; const newData = JSON.parse(JSON.stringify(data));
Spread
const data = [ { name: "David", age: 16000, }, { name: "David", age: 16000, }, { name: "David", age: 16000, }, { name: "David", age: 16000, }, { name: "David", age: 16000, }, { name: "David", age: 16000, }, { name: "David", age: 16000, } ]; const newData = [...data];
Rendered benchmark preparation results:
Suite status:
<idle, ready to run>
Run tests (2)
Previous results
Fork
Test case name
Result
With Serialization
Spread
Fastest:
N/A
Slowest:
N/A
Latest run results:
No previous run results
This benchmark does not have any results yet. Be the first one
to run it!
Autogenerated LLM Summary
(model
llama3.2:3b
, generated one year ago):
Let's dive into the world of JavaScript microbenchmarks on MeasureThat.net. **Benchmark Overview** The provided benchmark measures the performance difference between two approaches: using the spread operator (`...`) and serializing an array using `JSON.parse(JSON.stringify())`. The test creates an array with a large number of identical objects, and then creates a new copy of this array using both methods. **Options Compared** There are two options being compared: 1. **Spread Operator (`...`)**: This method creates a new array by spreading the original array's elements. 2. **Serialization using `JSON.parse(JSON.stringify())`**: This method serializes the original array, converts it to a string, and then parses it back into an array. **Pros and Cons of Each Approach** 1. **Spread Operator (`...`)** * Pros: + Creates a new copy of the array without modifying the original. + Efficient, as it only creates a new reference to each element. * Cons: + May not work as expected if the elements are mutable objects (e.g., arrays or dates). 2. **Serialization using `JSON.parse(JSON.stringify())`** * Pros: + Works with all types of objects, including mutable ones. * Cons: + Creates a deep copy of the array, which can be slower and more memory-intensive than the spread operator. **Library Used** There is no explicit library mentioned in the benchmark definition. However, it's worth noting that `JSON.parse(JSON.stringify())` relies on the `JSON` object, which is part of the JavaScript standard library. **Special JS Feature/Syntax** The benchmark uses a syntax feature called "template literals" (`\r\n \t{\r\n ... \t}`), which allows for multiline strings and template interpolation. This feature was introduced in ECMAScript 2015 (ES6) and is now widely supported by modern JavaScript engines. **Other Alternatives** There are other ways to create a copy of an array, such as using the `Array.prototype.slice()` method or the `Array.from()` method with the spread operator (`...`). For example: * `const newData = [...data];` (uses `Array.from()` and the spread operator) * `const newData = data.slice();` (uses `Array.prototype.slice()`) * `const newData = new Array(data.length);` (uses constructor-based approach) These alternatives may have different performance characteristics or trade-offs, depending on the specific use case.
Related benchmarks:
object spread vs immutable-js set vs object mutate
Immutable Map vs Ordered Map vs List
Immutable.Set Union vs Constructing a new plain JS Set
Immutable.Set Union vs Constructing a new plain JS Set - small
immutable vs Native Javascript Map With Read
Comments
Confirm delete:
Do you really want to delete benchmark?