Benchmark: array filtering with some vs array filtering with includes

Script Preparation code:

var listOfObjects_1 = [{id: 1, name: '1'}, {id: 2, name: '2'}, {id: 5, name: '5'}]
var listOfObjects_2 = [{id: 1, name: '1'}, {id: 2, name: '2'}, {id: 5, name: '4'}]

Tests:

array filtering with some
listOfObjects_1.filter(selectedItem => listOfObjects_2.some(item => item.id === selectedItem.id) )
array filtering with includes
var ids_1 = listOfObjects_1.map(o => o.id) listOfObjects_2.filter(o => ids_1.includes(o.id))

Rendered benchmark preparation results:

Suite status: <idle, ready to run>

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Test case name	Result
array filtering with some
array filtering with includes

Fastest: N/A

Slowest: N/A

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Autogenerated LLM Summary (model gemma2:9b, generated one year ago):

LLMs can make mistakes. Check important info.

This benchmark compares two different methods of filtering an array in JavaScript:

**Method 1: `filter` with `some`:**

*  The code uses the `filter()` method on the first array (`listOfObjects_1`). 
* For each object in `listOfObjects_1`, it checks if any object in the second array (`listOfObjects_2`) has an identical `id`. The `some()` method is used for this check. If a matching `id` is found, the object is included in the filtered result.

**Method 2: `filter` with `includes`:**

* This method first creates a new array (`ids_1`) containing only the `id` values from `listOfObjects_1`.
* Then, it uses the `filter()` method on `listOfObjects_2`, checking if each object's `id` exists in the `ids_1` array using the `includes()` method.

**Pros and Cons:**

* **Method 1 (`some`)**:
    *  **Pro:** Can be more expressive as it directly checks for a match within another array.
    * **Con:** Potentially slower because `some()` iterates through the entire second array for each object in the first array.

* **Method 2 (`includes`)**:
    * **Pro:** Potentially faster because `includes()` is generally optimized and only iterates until a match is found or the end of the array.
    * **Con:** Requires an extra step to create the `ids_1` array, which might add a negligible overhead.

**Alternatives:**

* **Set**: You could use Sets to efficiently check for existence of IDs: 
   - Create a Set from `listOfObjects_1`'s IDs. Then filter `listOfObjects_2` by checking if each object's ID is present in the set.

* **Hash Map (Object):** Use an Object to store IDs and their corresponding values from `listOfObjects_1`.  Then, iterate through `listOfObjects_2` and check for the presence of IDs in this hash map.

Let me know if you have any other questions!

Related benchmarks:

array filtering with some vs array filtering with includes (version: 0)

Return only objects with same id

Comparing performance of: array filtering with some vs array filtering with includes

Created: 5 years ago by: Guest

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array filtering with some

array filtering with includes

Suite status: <idle, ready to run>

Fastest: N/A

Slowest: N/A

No previous run results

Autogenerated LLM Summary (model gemma2:9b, generated one year ago):