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Array join and let unique values in return v2
(version: 0)
Comparing performance of:
c vs D vs E
Created:
5 years ago
by:
Guest
Jump to the latest result
Script Preparation code:
var a1 = [...Array(10000)].map((x, i) => ["Vijendra", "Singh", "ab", "cd", "ef", "gh", "ij", "kl", "mn", "op"][i % 10]); var a2 = [...Array(10000)].map((x, i) => ["Singh", "Shakya", "ab", "cd", "zz", "xx", "ij", "kl", "AA", "BB"][i % 10]); function K(arr1,arr2) { let r=[], h={}; while(arr1.length) { let e = arr1.shift(); if(!h[e]) h[e]=1 && r.push(e); } while(arr2.length) { let e = arr2.shift(); if(!h[e]) h[e]=1 && r.push(e); } return r; }
Tests:
c
return new Set([...a1,...a2]);
D
c=a1.concat(a2); return c.filter((item, pos) => c.indexOf(item) === pos);
E
return K(a1,a2);
Rendered benchmark preparation results:
Suite status:
<idle, ready to run>
Run tests (3)
Previous results
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Test case name
Result
c
D
E
Fastest:
N/A
Slowest:
N/A
Latest run results:
No previous run results
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Autogenerated LLM Summary
(model
llama3.2:3b
, generated one year ago):
**Overview of the Benchmark** The provided JSON represents a JavaScript microbenchmark on MeasureThat.net, which compares different approaches to remove duplicate values from two arrays. **Benchmark Definition** The benchmark is defined by three test cases: 1. `return new Set([...a1,...a2]);`: This approach uses the built-in `Set` data structure in JavaScript to eliminate duplicates. 2. `c=a1.concat(a2); return c.filter((item, pos) => c.indexOf(item) === pos);`: This approach uses the `concat()` method to concatenate the two arrays and then filters out duplicate values using an arrow function. 3. `return K(a1,a2);`: This approach defines a custom function `K` that takes two arrays as input and returns an array with unique values. **Options Compared** The benchmark compares three different approaches: * Using `Set` to eliminate duplicates * Using `concat()` and filtering to eliminate duplicates * Defining a custom function `K` to eliminate duplicates **Pros and Cons of Each Approach** 1. **Using `Set`**: * Pros: Efficient, concise, and easy to understand. * Cons: May not be suitable for very large arrays due to memory constraints, and some browsers may have issues with `Set` performance. 2. **Using `concat()` and filtering**: * Pros: Can handle large arrays, but may be slower than using `Set`. * Cons: More verbose and complex, with additional overhead from concatenating arrays and searching for duplicates. 3. **Defining a custom function `K`**: * Pros: Allows for fine-grained control over the elimination of duplicates. * Cons: More complex to implement, may require more memory, and may have performance issues due to the custom function. **Library Used** The benchmark uses the built-in `Set` data structure in JavaScript, which is a part of the standard library. **Special JS Feature or Syntax** There are no special JS features or syntax used in this benchmark. The code is straightforward and easy to understand. **Other Alternatives** Other alternatives for eliminating duplicates in arrays include: * Using a `Map` data structure instead of `Set` * Using an object with unique keys * Using a custom implementation with manual iteration over the array * Using a third-party library like Lodash or Underscore.js However, using `Set` is often the most efficient and concise way to eliminate duplicates in modern JavaScript. **Benchmark Result** The latest benchmark result shows that the approach using `Set` (Test Name: "E") performs best with an execution rate of 5118944.5 executions per second. The approach using `concat()` and filtering (Test Name: "D") performs slower, with an execution rate of 458.4192810058594 executions per second. The custom function implementation (Test Name: "C") performs the slowest, with an execution rate of 6.702840805053711 executions per second.
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