Benchmark: 11111 vs 222222 - MeasureThat.net

Tests:

1
function isAnagram(stringA, stringB) { const sanitizeString = function (str) { return str.toLowerCase().replace(/[^a-z\d]/g, '').split('').sort().join(''); } return sanitizeString(stringA) == sanitizeString(stringB) }
2
function isAnagram(stringA, stringB) { function createCharMap(text) { let charMap = {} for (let char of text) { if (charMap.hasOwnProperty(char)) { charMap[char]++ } else { charMap[char] = 1 } } return charMap } if (stringA.length === stringB.length) { let stringAMap = createCharMap(stringA) let stringBMap = createCharMap(stringB) for (let char in stringAMap) { if (stringAMap[char] !== stringBMap[char]) { return false } } return true } else { return false } }

Rendered benchmark preparation results:

Suite status: <idle, ready to run>

Previous results

Test case name	Result
1
2

Fastest: N/A

Slowest: N/A

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Autogenerated LLM Summary (model llama3.2:3b, generated one year ago):

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Let's break down the benchmark and explain what's being tested.

**Benchmark Overview**

The benchmark measures the performance of two approaches to determine if two input strings are anagrams of each other. An anagram is a word or phrase formed by rearranging the letters of another word or phrase, typically using all the original letters exactly once.

**Approach 1: Using the `sort()` method (Benchmark Definition 2)**

This approach uses the built-in `sort()` method to sort the characters in each string and then compares the sorted arrays. Here's a summary:

* Pros:
	+ Simple and easy to implement
	+ Uses a standard JavaScript method
* Cons:
	+ Has a high time complexity due to sorting (O(n log n))
	+ May be slower for large input strings

**Approach 2: Creating a character map (Benchmark Definition 1)**

This approach uses an object to count the occurrences of each character in both input strings and then compares these maps. Here's a summary:

* Pros:
	+ Has a better time complexity (O(n)) since it only iterates over each string once
	+ Can be faster for large input strings
* Cons:
	+ Requires more memory to store the character map
	+ May have additional overhead due to object creation and lookup

**Library Usage**

There is no explicit library mentioned in either benchmark definition. However, the `sort()` method used in Approach 1 is a built-in JavaScript method.

**Special JS Feature/Syntax**

There are no special JavaScript features or syntax used in these benchmarks.

**Other Considerations**

* The benchmark uses a test case with varying input strings ("11111" and "222222") to test both approaches.
* The `ExecutionsPerSecond` metric measures the number of executions per second, which provides insight into the performance of each approach under different conditions.
* The benchmark results are likely influenced by factors such as JavaScript engine optimizations, browser configuration, and system resources.

**Alternative Approaches**

Other possible approaches to determine if two strings are anagrams include:

1. Using a frequency table or hash map to count character occurrences.
2. Employing a more complex algorithm that takes into account character frequencies and permutations.
3. Utilizing libraries or frameworks like `lodash` or `ramda`, which provide optimized implementations for string manipulation tasks.

Keep in mind that the chosen approach depends on the specific requirements and constraints of your project, such as performance, memory usage, and development simplicity.

Related benchmarks:

11111 vs 222222 (version: 0)

Comparing performance of: 1 vs 2

Created: 5 years ago by: Guest

Jump to the latest result

1

2

Suite status: <idle, ready to run>

Fastest: N/A

Slowest: N/A

No previous run results

Autogenerated LLM Summary (model llama3.2:3b, generated one year ago):