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spread vs push vs ifSpread vs ifPush
(version: 0)
Comparing performance of:
spread vs push vs ifPush vs ifSpread
Created:
5 years ago
by:
Guest
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Script Preparation code:
var arr1 = [1,32,4,34,5,6,7,34,5,6]; var arr2 = [5,232,545,56,223,5,1,6,30];
Tests:
spread
var resultSpread = [...arr1, ...arr2];
push
for (let index = 0; index < arr2.length; index++) { const element = arr2[index]; arr1.push(element); }
ifPush
for (let index = 0; index < arr2.length; index++) { const element = arr2[index]; if (arr1.findIndex((item) => item === element) < 0) { arr1.push(element); } }
ifSpread
for (let index = 0; index < arr2.length; index++) { const element = arr2[index]; if (arr1.findIndex((item) => item === element) < 0) { arr1 = [...arr1, element]; } }
Rendered benchmark preparation results:
Suite status:
<idle, ready to run>
Run tests (4)
Previous results
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Test case name
Result
spread
push
ifPush
ifSpread
Fastest:
N/A
Slowest:
N/A
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Autogenerated LLM Summary
(model
llama3.2:3b
, generated one year ago):
Let's break down what's being tested in this benchmark. The benchmark is comparing four different approaches to concatenate (join) two arrays, `arr1` and `arr2`, into a new array: 1. Using the spread operator (`...`) 2. Using the `push()` method 3. Using the `findIndex()` method with an if statement to check for existence before pushing 4. Using the spread operator (`...`) inside the `arr1` array assignment Let's analyze each approach and its pros and cons: **1. Spread Operator (`...`)** * Pros: concise, readable, and efficient. It creates a new array by copying elements from `arr2` and appending them to `arr1`. * Cons: may incur additional overhead due to the creation of a new array. **2. Push() Method** * Pros: straightforward, easy to understand, and efficient for large arrays. * Cons: requires iterating over `arr2` and pushing each element into `arr1`, which can be slower than using spread or findIndex. **3. findIndex() Method with if Statement** * Pros: cleverly avoids creating a new array, only iterating over `arr2` once, and efficiently checks for existence in `arr1`. * Cons: may require careful handling of edge cases (e.g., when `arr1` is empty), can be less readable than other approaches. **4. Spread Operator (`...`) Inside Array Assignment** * Pros: similar to the spread operator approach, but creates a new array by copying elements from `arr2` and assigning it to `arr1`. * Cons: slightly slower due to the additional assignment operation. Other considerations: * The benchmark is testing these approaches on a large array of numbers (`[1, 32, 4, ...]`) which might affect performance. * The use of `findIndex()` with an if statement allows for efficient existence checks in `arr1` without creating a new array. * The spread operator and spread operator inside array assignment are similar approaches but differ slightly in implementation. Now, about the libraries used: None of the benchmark's test cases explicitly use any external libraries. However, it is worth noting that modern JavaScript environments (like those tested by MeasureThat.net) come with built-in functions like `findIndex()` which are equivalent to using external libraries like Lodash. Special JS features or syntax: There are no special features or syntax used in this benchmark beyond what's considered standard for modern JavaScript. The use of spread operator and `findIndex()` is a common, idiomatic way to accomplish these operations in recent JavaScript versions (ES6+). For those interested in alternatives: Other methods for concatenating arrays include: * Using the `concat()` method: `arr1.concat(arr2)` * Using `Array.prototype.reduce()`: `[...arr1, ...arr2]` * Using `Array.prototype.forEach()`: `arr1.forEach((item) => arr2.push(item));` Each of these alternatives has its own pros and cons, but they are generally less efficient or more verbose than the approaches tested in this benchmark.
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