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isArray - fork1
(version: 0)
Array.isArray vs Object.prototype.toString vs [].constructor vs instanceof
Comparing performance of:
Array.isArray vs instanceof vs [].constructor vs Object.prototype.toString
Created:
5 years ago
by:
Registered User
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Script Preparation code:
var toStr = Object.prototype.toString function toStrCase(obj){ return obj.toString() === '[object Array]' } function consCase(obj){ return obj?.constructor === Array } function instCase(obj){ return obj instanceof Array } var isArray = Array.isArray
Tests:
Array.isArray
isArray([])
instanceof
instCase([])
[].constructor
consCase([])
Object.prototype.toString
toStrCase([])
Rendered benchmark preparation results:
Suite status:
<idle, ready to run>
Run tests (4)
Previous results
Fork
Test case name
Result
Array.isArray
instanceof
[].constructor
Object.prototype.toString
Fastest:
N/A
Slowest:
N/A
Latest run results:
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Autogenerated LLM Summary
(model
llama3.2:3b
, generated one year ago):
Let's break down the provided benchmark and its options. **Benchmark Overview** The benchmark, `isArray - fork1`, tests four different approaches to determine if an object is an array: 1. `Array.isArray` 2. `Object.prototype.toString` (specifically, checking for `[object Array]`) 3. `[].constructor` (checking if the constructor is `Array`) 4. `instanceof Array` **Approach 1: `Array.isArray`** This approach uses the built-in `Array.isArray()` method to check if an object is an array. Pros: * Fast and efficient, as it's a native method. * Well-documented and widely supported. Cons: * May not work correctly for certain types of objects (e.g., `Map`, `Set`). * Can be slower than other approaches in some cases. **Approach 2: `Object.prototype.toString`** This approach uses the `toString()` method on the object to check if it's an array. The method is called with `[object Array]` as a string argument to specifically test for arrays. Pros: * Works well for most objects, including `Map` and `Set`. * Can be faster than other approaches in some cases. Cons: * May not work correctly for certain edge cases (e.g., objects with `toString()` overridden). * Requires JavaScript engine support for the `Object.prototype.toString()` method. **Approach 3: `[].constructor`** This approach uses the constructor of an empty array (`[]`) to check if an object is an array. The `instanceof` operator is used to compare the object's constructor with the array constructor. Pros: * Fast and efficient, as it's a simple comparison. * Works well for most objects, including `Map` and `Set`. Cons: * May not work correctly for certain edge cases (e.g., objects with overridden constructors). * Requires JavaScript engine support for the `instanceof` operator. **Approach 4: `instanceof Array`** This approach uses the `instanceof` operator to check if an object is a direct instance of the `Array` constructor. Pros: * Works well for most objects, including `Map` and `Set`. * Is a straightforward and easy-to-understand approach. Cons: * May be slower than other approaches in some cases. * Requires JavaScript engine support for the `instanceof` operator. **Other Considerations** When choosing an approach, consider the specific use case and requirements. For example, if you need to handle `Map` or `Set` objects, Approach 2 (`Object.prototype.toString`) might be a better choice. If you're targeting older browsers that don't support `instanceof`, Approach 4 might not work. **Library** The benchmark uses no external libraries. The tests are self-contained and rely on built-in JavaScript methods and operators. **Special JS Features/Syntax** There is no mention of special JavaScript features or syntax in the provided benchmark.
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