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TuggaKoden
(version: 0)
Comparing performance of:
Math vs Bitwise
Created:
9 years ago
by:
Guest
Jump to the latest result
Script Preparation code:
var number = 12.4;
Tests:
Math
Math.floor(number)
Bitwise
number | 0
Rendered benchmark preparation results:
Suite status:
<idle, ready to run>
Run tests (2)
Previous results
Fork
Test case name
Result
Math
Bitwise
Fastest:
N/A
Slowest:
N/A
Latest run results:
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Autogenerated LLM Summary
(model
llama3.2:3b
, generated one year ago):
I'd be happy to explain the benchmark being tested on MeasureThat.net. **What is being tested?** The benchmark being measured is a simple arithmetic operation: dividing 12.4 by 0 using the `/` operator (for JavaScript) and using bitwise operations (`number | 0`). These two approaches are compared to determine which one performs better in terms of execution speed. **Options compared:** 1. **Math Division (/)**: This option uses the built-in `Math.floor()` function, which returns the largest integer less than or equal to the given number. 2. **Bitwise Operation (`|`)**: This option uses a bitwise OR operation with 0, effectively truncating the decimal part of the number. **Pros and Cons:** * **Math Division (/):** + Pros: - More intuitive and readable code - Less error-prone (no risk of integer overflow) + Cons: - May be slower due to function call overhead - Requires more CPU instructions * **Bitwise Operation (`|`):** + Pros: - Faster execution speed due to fewer CPU instructions - Can be optimized by the JavaScript engine + Cons: - Less intuitive and less readable code - Risk of integer overflow if not used carefully **Library/Functionality:** In this benchmark, no external libraries are explicitly mentioned. However, the `Math.floor()` function is a built-in part of the JavaScript language. **Special JS Feature/Syntax:** The bitwise OR operation (`|`) is a special operator in JavaScript that performs a binary operation on its operands. It's often used for integer arithmetic or to clear bits in an integer value. **Other Alternatives:** If you were to use `Math.floor()` instead of the `/` operator, you could also consider using other methods like: * Multiplying by a power of 10 (e.g., `number * 1000`) and then taking the floor * Using a more specialized library or function for truncating decimal numbers In terms of alternative implementations for the bitwise operation, you could use: * Multiplying by the binary representation of 0 (`|` operator is essentially equivalent to multiplying by 256 if you consider two's complement) * ORing with zero and then casting to integer using `Number()` Keep in mind that these alternatives might not be as readable or intuitive as the original implementation, but they can offer performance benefits under specific circumstances.
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